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Lemur [1.5K]
3 years ago
6

At Pizzazz Pizza, the total price for 5 large pizzas plus 2 small

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
4 0
The prize of a medium pizza is $9.50
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Help me plz. I dont understand.
Ahat [919]
For this, you would use simultaneous equations.

w=walnuts
a=almonds

3w+6a=51
5w+4a=55

Find a way to make one of the unknowns equal. since we are trying to work out the price of a pound of walnuts, I am going to make a equal on each side to leave us with w. This leaves us with:

15w+12a=165
6w+12a=102

Then take them away to leave w:

9w=163

Then solve:

w=163/9
= 18.11111111...

Then round it to 2 decimal places as the measurement is currency.

So 1 pound of walnuts equals $18.11
3 0
3 years ago
Let u,v,wu,v,w be three linearly independent vectors in R7R7. Determine a value of kk, k=k= , so that the set S={u−3v,v−2w,w−ku}
11Alexandr11 [23.1K]

Answer:

1/6

Step-by-step explanation:

For a set of vectors a, b and c to be linearly dependent, the linear combination of the set of vectors must be zero.

C1a + C2b + C3c = 0

From the question, we are given the set S={u−3v,v−2w,w−ku}, the corresponding vectors are a(0, -3, 1), b(-2,1,0) and c(1,0,-k)

The values in parenthesis are the ccoefficients of w, v and u respectively.

On writing this vector as a linear combination, we will have;

C1(0, -3, 1) + C2(-2,1,0) + C3(1,0,-k) = (0,0,0)

0-2C2+C3 = 0........ 1

-3C1+C2 = 0 ........... 2

C1-kC3 = 0 ….......... 3

From equation 2, 3C1 = C2

Substituting into 1, -2(3C1)+C3 = 0

-6C1+C3 = 0

-6C1 = -C3

6C1 = C3.…..4

Substitute 4 into 3 to have

C1-k(6C1) = 0

C1 = k6C1

6k = 1

k = 1/6

Hence the value of k for the set of vectors to be linearly dependent is 1/6

6 0
3 years ago
A Sqrt &amp;<br> B Sqrt 29<br> c 7<br> c 29
Effectus [21]

Answer: hi

Step-by-step explanation:

hi

4 0
3 years ago
Name the plane that contains points A, D, and E.
Verdich [7]

Answer:

Plane T

Step-by-step explanation:

The given points A, D, and E are shown as being on the plane T as follows

Point a lays on the boundary of the boundary between plane S and plane T

Points D and E are points on a line DE that is on the plane T

Therefore, given that the line DE and the point A all lay on the same plane T, the plane that contains points A, D, and E, is plane T.

6 0
3 years ago
Please help me answer this
Ronch [10]

Answer:

10.77

Step-by-step explanation:

by using Pythagoras theorem we can find the distance between the points,

so...

distance between the points, which is the hypotenuse will be xy

difference between the y coordinates will be dy

difference between the x coordinates will be dx

according to pythagoras theorem,

xy^{2} = dx^{2} +  dy^{2} \\xy^{2} = (-6-(-2))^{2} + (-5-5)^{2}\\xy^{2} =(-4)^{2} +(-10)^{2} \\xy^{2} =16+100\\xy^{2} =116\\xy =\sqrt{116} \\xy=10.77

8 0
3 years ago
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