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3 years ago

Select two figures that have the same volume.

Mathematics

2 answers:

Dmitriy789 [7]3 years ago

8 0

It is an f
Chen’s
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vova2212 [387]3 years ago

3 0

Answer: The last one and the second one both have a volume of 603.18

Step-by-step explanation:

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The answer is 4.5 because you are multiplying 1.5 times 3 = 4.5

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3 years ago

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Twenty-four is 30% of what number?

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24 / 30 x 100 = 80

answer: Twenty-four is 30% of 80

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Plz Help???

GREYUIT [131]

1.
12 liters of 26% acid solution contain $26\% \times 12=0.26 \times 12=3.12$ liters of acid.
x liters of 40% acid solution contain $40\%x=0.4x$ liters of acid.
The third solution is made from the two mixed solution so its volume is $12+x$ , and the volume of acid in it is $0.4x+3.12$ . Its concentration is 33% or 0.33.
The concentration of a solution is the volume of the solution divide by the volume of acid in it.

$\frac{0.4x+3.12}{12+x}=0.33 \\ 0.4x+3.12=0.33(12+x) \\ 0.4x+3.12=3.96+0.33x \\
0.07x=0.84 \\
x=12$

The answer is B.

2.
12 liters of 16% acid solution contain $16\% \times 12=0.16 \times 12=1.92$ liters of acid.
x liters of 40% acid solution contain $40\%x=0.4x$ liters of acid.
The volume of the third solution is $12+x$ , and the volume of acid in it is $0.4x+1.92$ . Its concentration is 32% or 0.32.

$\frac{0.4x+1.92}{12+x}=0.32 \\
0.4x+1.92=0.32(12+x) \\
0.4x+1.92=3.84+0.32x \\
0.08x=1.92 \\
x=24$

The answer is B.

3.
16 liters of 18% acidsolution contain $18\% \times 16=0.18 \times 16=2.88$ liters of acid.
x liters of 27% acid solution contain $27\%x=0.27x$ liters of acid.
The volume of the third solution is $16+x$ , and the volume of acid in it is $0.27x+2.88$ . Its concentration is 21% or 0.21.

$\frac{0.27x+2.88}{16+x}=0.21 \\
0.27x+2.88=0.21(16+x) \\
0.27x+2.88=3.36+0.21x \\
0.06x=0.48 \\
x=8$

The answer is A.

5 0

4 years ago

The volume of a cylinder varies jointly with the square of its radius and with its height: Cylinder A has a volume of 254.34 cub

adelina 88 [10]

Answer:

The volume of the cylinder B is 251.2 cubic inches.

Step-by-step explanation:

Given : The volume of a cylinder varies jointly with the square of its radius and with its height: Cylinder A has a volume of 254.34 cubic inches and has a radius of 3 inches and a height of 9 inches.

To find : What is the volume of cylinder B, which has a radius of 4 inches and a height of 5 inches?

Solution :

The volume of a cylinder varies jointly with the square of its radius and with its height i.e. the volume is

$V=k r^2h$

Where, k varies jointly

Now, Cylinder A has a volume of 254.34 cubic inches and has a radius of 3 inches and a height of 9 inches

i.e. V=254.34 cubic inches , r=3 inches and h=9 inches

Substitute values in the formula,

$254.34=k\times3^2\times 9$

$254.34=k\times81$

$k=\frac{254.34}{81}$

$k=3.14$

Now, The volume of cylinder B, which has a radius of 4 inches and a height of 5 inches is given by,

$V=3.14r^2h$

$V=3.14\times 4^2\times 5$

$V=3.14\times 16\times 5$

$V=251.2in^3$

Therefore, The volume of the cylinder B is 251.2 cubic inches.

3 0

3 years ago

Abc daycare wants to build a fence to enclose a rectangular playground. the area of the playground is 930 square feet. the fence

Dahasolnce [82]

Xy = 940

and 

Cost = 5(2x) + 5y + 10y (I chose y to be the side with brick). The cost equation simplifies to: 

C = 10x + 15y 

Replace y in the cost equation with 940/x: 

C = 10x + 15(940/x) 

C = 10x + 14100/x <---this is the equation you need to minimize. 

C' = 10 - 14100/x^2 

10 - 14100/x^2 = 0 

14100/x^2 = 10 

x^2 = 14100/10 = 1410 

x = sqrt(1410) = 37.55 

y = 25.03 <---this is the length of the brick fence.

4 0

3 years ago