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Murljashka [212]
3 years ago
7

DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [infinity] e−stf(t) dt 0 i

s said to be the Laplace transform of f, provided that the integral converges. to find ℒ{f(t)}. (Write your answer as a function of s.) f(t) = cos(t), 0 ≤ t < π 0, t ≥ π ℒ{f(t)} = (s > 0)
Mathematics
1 answer:
iragen [17]3 years ago
6 0

f(t)=\begin{cases}\cos t&\text{for }0\le t

Write f(t) in terms of the step function u(t):

f(t)=(u(t)-u(t-\pi))\cos t

where the step function is defined by

u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t

The Laplace transform is then

\mathcal L_s\{f(t)\}=F(s)=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi\cos t\,e^{-st}\,\mathrm dt

\implies F(s)=\dfrac{(e^{-\pi s}+1)s}{s^2+1}

(if you're stuck on the integral, try integrating by parts)

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Let's solve ~

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