There are 9 different colors of paint to choose from. Out of the 9 colors, how many ways can 4 different colors be chosen?
2 answers:
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Answer:
x=1, y=-5
Step-by-step explanation:
Given equations are:
In order to solve the equation
Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them
So,
Eqn 1 becomes
15x+50y=-235
Eqn 2 becomes
15x-21y=120
Subtracting 2 from a
15x+50y - (15x-21y) = -235-120
15x+50y-15x + 21y = -355
71y = -355
y = -355/71
y =-5
Putting y= -5 in eqn 1
3x+10(-5) = -47
3x -50 = -47
3x = -47+50
3x = 3
x = 3/3
x = 1
Hence the solution is:
x=1, y=-5
Answer:
Step-by-step explanation:
This expression was kind of trial and error for me seeing as I'm not really good at logic, but this is pretty basic. There are three possible places the parentheses can be placed (assuming each pair holds 2 terms);
The answer to the first expression would be 45, which is not equal to 11.
The answer to the second expression would be 15, which is also not equal to 11.
The answer to the last expression is 11, so that is the correct answer.
Hope this helped :D
- Shay
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.
The total number of aces is approximately 167, 12 or more. The SE is 12 out of 1000, which is 1.2 percent.
The percentage of aces is expected to be around 16.67% , or 1.2%.
