What is the volume of a cylinder with a radius of 7.5 cm and a height of 20 cm
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Answer:
492
Step-by-step explanation:
As per the given data of the question:
Total number of students = 2504
Number of students in Java (J) = 1876
Number of students in Linux (L) = 999
Number of students in C = 345
J∩L = 876
L∩C = 231
C∩J = 290
L∩J∩C = 189
Now according to Venn-diagram as drawn below:
Number of students haven taken courses in Java and Linux both only
= J∩L - L∩J∩C
= 876 - 189
= 687
Number of students haven taken courses in Java and C both only
= C∩J - L∩J∩C
= 290 - 189
= 101
Number of students haven taken courses in C and Linux both only
= L∩C - L∩J∩C
= 231 - 189
= 42
Therefore,
Number of students only in Java = 1876 - 687 - 189 - 101 = 899
Number of students only in Linux = 999 - 687 - 189 - 42 = 81
Number of students only in C = 345 - 42 - 189 - 101 = 13
So,
Number of students who have not taken a course in any of these three subjects
= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42
= 492
Hence, the students who have not taken a course in any of these three subjects = 492.
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221