16 times 2 is 32. 81-32 is....49. Did I answer your question?
Answer:
(x, y) = (25, 18)
Step-by-step explanation:
Use the angle sum theorem. You can write equations for the right angle and for the linear angle.
(x +11) +(3y) = 90 . . . . sum of angles making the right angle
(y +7) +90 +65 = 180 . . . . sum of angles making the linear angle
From the second equation, we have ...
y = 18 . . . . subtract 162
Substituting into the first equation gives ...
x + 11 + 3(18) = 90
x = 25 . . . . subtract 65
The values of x and y are 25 and 18, respectively.
_____
<em>Check</em>
VQ = 18+7 = 25
QR = 25 +11 = 36
RS = 3·18 = 54
ST = 65
The totals are 36 +54 = 90; 25 +36 +54 +65 = 180, as required.
Answer:
The first one doesn't help while both the second and third helps in finding the vertices
Step-by-step explanation:
Answer:
Domain is your x max and Min, Range is your y max and Min
Step-by-step explanation:
Domain would be -5 to 8 or (-5,8)
range would be -3 to 2 or (-3,2)
The x-intercepts of the given quadratic function are -2 and 9.
What is a quadratic function?
A quadratic function is a function represented as, f(x) = ax2 + bx + c, with a, b, and c being integers and a not equal to zero. A parabolic curve represents the graph of a quadratic function.
A polynomial's highest degree reveals how many roots the polynomial has. The values for which the polynomial's numerical value is equal to zero are known as a polynomial's roots (also known as zeros of a polynomial). On a graph, the points where the polynomial's graph and the x-axis cross are the roots (x-intercepts).
Roots of the Quadratic Equation
Due to its degree of 2, a quadratic function can only have a maximum of two real roots. In order to find the roots of a quadratic equation, we equate its factors to 0. Thus, in this case, we have,
(x+2)*(x-9)=0
∴ x+2=0
⇒ x=-2
Similarly,
x-9=0
⇒ x=9
Hence, the x- intercepts of the given quadratic function come out to be -2 and 9.
Learn more about a quadratic function here:
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