All categories

2 years ago

Pls help me on this!

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

4 0

It’s b :) haha i got it right

You might be interested in

A telemarketer earns a base salary of $3,000 per month, plus an annual bonus of 2.5% of total sales above $250,000. Which functi

gavmur [86]

Answer:

c S(x) = 12(3,000) + 0.025(x – 250,000)

Step-by-step explanation:

I got it right

6 0

2 years ago

Read 2 more answers

PLS HELP !!!

alisha [4.7K]

Step-by-step explanation:

I guess we only need to add 2 hours and 38 minutes to the depart times to get arrival, and deduct 2 hours and 38 minutes from arrival to get departure.

a) 05 00 -> 07 38

b) 07 20 -> 09 58

c) 08 40 -> 11 18

d) 10 58 -> 13 36

e) 15 45 -> 18 23

f) 18 22 -> 21 00

g) 18 39 -> 21 17

h) 20 47 -> 23 25

4 0

2 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured parallel to a line

Ber [7]

Answer:

The distance is:

$\displaystyle\frac{3\sqrt{142}}{10}$

Step-by-step explanation:

We re-write the equation of the line in the format:

$\displaystyle\frac{x+2}{3}=\frac{y+\frac{3}{2}}{2}=\frac{z+\frac{4}{3}}{\frac{5}{3}}$

Notice we divided the fraction of y by 2/2, and the fraction of z by 3/3.

In that equation, the director vector of the line is built with the denominators of the equation of the line, thus:

$\displaystyle\vec{v}=\left< 3, 2, \frac{5}{3}\right>$

Then the parametric equations of the line along that vector and passing through the point (-2, 3, -4) are:

$x=-2+3t\\y=3+2t\\\displaystyle z=-4+\frac{5}{3}t$

We plug them into the equation of the plane to get the intersection of that line and the plane, since that intersection is the image on the plane of the point (-2, 3, -4) parallel to the given line:

$\displaystyle x+y+z=3\to -2+3t+3+2t-4+\frac{5}{3}t=3$

Then we solve that equation for t, to get:

$\displaystyle \frac{20}{3}t-3=3\to t=\frac{9}{10}$

Then plugging that value of t into the parametric equations of the line we get the coordinates of the intersection:

$\displaystyle x=-2+3\left(\frac{9}{10}\right)=\frac{7}{10}\\\displaystyle y=3+2\left(\frac{9}{10}\right)=\frac{24}{5} \\\displaystyle z=-4+\frac{5}{3}\left(\frac{9}{10}\right)=-\frac{5}{2}$