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miv72 [106K]
3 years ago
15

What is the answer to this problem?

Mathematics
1 answer:
Andrei [34K]3 years ago
5 0

i think the best answer for this question is A)

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Please help me!!!!!!!!!!!!!!
arsen [322]

Ans

184 sq meter

Step-by-step explanation:

Area of the cuboid box = (2*FA)+(2*SA)+(2*TA)

Where FA= Front face area

SA= Side face area

TA= top face are

Here FA= length * breadth = 10*6=60 sq meter

SA= 10*2= 20 sq meter

TA= 6*2= 12 sq meter

So area of box= 2*60+2*20+2*12= 184 sq meter

7 0
3 years ago
HELP ME. LOOK AT PICTURE
KATRIN_1 [288]
It would be in the top left corner
5 0
3 years ago
Read 2 more answers
The price of a gallon of unleaded gas was $2.81 yesterday l. Today, the price rose to $2.88. Find the percentage increase
Allisa [31]

Answer:

7%

Step-by-step explanation:

4 0
3 years ago
Cost to store<br> Percent of markup: 15%<br> Selling price: $85.10
kotykmax [81]
Cost to store= $74.00
7 0
3 years ago
What is the simplified form of the expression? 6/√5−√2
tester [92]

Answer:

The expression can be simplified into 2\,\sqrt{5} +2\sqrt{2}

with no square roots in the denominator

Step-by-step explanation:

We are considering the expression  \frac{6}{\sqrt{5}-\sqrt{2}  }  which I believe is what you wanted to type in your question.

The idea behind simplification of the expression, is normally associated with the rationalization of the denominator by eliminating irrational numbers from it. This means to get rid of any "irrational" number expression (like in this example, the square root of non-perfect square numbers (\sqrt{5}\,\,\,and \,\,\sqrt{2}).

We proceed by writing this quotient in an equivalent form by multiplying its numerator and its denominator by what is called the "conjugate" of the denominator. In our case, multiply by " (\sqrt{5} +\sqrt{2}) ", because such product will allow the denominator to become a rational number:

\frac{6}{\sqrt{5}-\sqrt{2}  }\,*\,\frac{(\sqrt{5}+\sqrt{2} )}{(\sqrt{5}+\sqrt{2}) } =\frac{6\,(\sqrt{5}\,+\,\sqrt{2} )}{\sqrt{5}^2-\sqrt{2}^2 }=\frac{6\,(\sqrt{5}\,+\,\sqrt{2} )}{3}=2\,\sqrt{5} +2\sqrt{2}

where we find all square roots eliminated from the denominator

5 0
3 years ago
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