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2 years ago

A test was given to a group of students. The grades and gender are summarized below

Mathematics

1 answer:

faust18 [17]2 years ago

4 0

Answer:

<h3>★ <u>11/</u><u>3</u><u>0</u> is the right answer. ★</h3>

Step-by-step explanation:

Number of male students who got 'A' in the test is 11
Number of female students who got 'A' in the test is 19
Total students who got 'A' in the test is 30
Probability that the male student got an 'A' is P(A | male) = (Number of male students who got 'A' in the test)/(Number of total students who got 'A' in the test) = <em><u>11/</u></em><em><u>3</u></em><em><u>0</u></em>

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please solve all of them Elaine bought a total of 15 shirts and pairs of pants She bought 7 more shirts then pants how many of e

mihalych1998 [28]

Answer

Question 1

4 pants

11 shirts

Question 2

Shady has 30 video games.

Preston has 19 video games.

Question 3

1 muffin costs $1.5

1 quart of milk costs $3

Explanation

Question 1

Let the number of shirts be s

Let the number of pants be p

She bought a total of 15 shirts and shirts

s + p = 15

She bought 7 more shirts than pants.

s = 7 + p

So, we can solve the simultaneous equation.

s + p = 15

s = 7 + p

Substitute for s in equation 1

s + p = 15

7 + p + p = 15

7 + 2p = 15

2p = 15 - 7

2p = 8

Divide both sides by 2

(2p/2) = (8/2)

p = 4 pants

s = 7 + p = 7 + 4 = 11 shirts

Question 2

Let the number of games Shady has be s

Let the number of games Preston has be p

Together, they have a total of 49 video games

s + p = 49

Shady has 11 more games than Preston.

s = 11 + p

So, we can solve the simultaneous equation.

s + p = 49

s = 11 + p

Substitute for s in equation 1

s + p = 49

11 + p + p = 49

11 + 2p = 49

2p = 49 - 11

2p = 38

Divide both sides by 2

(2p/2) = (38/2)

p = 19 video games

s = 11 + p = 11 + 19 = 30 video games

Question 3

Let the cost of a muffin be m

Let the cost of a quart of milk be q

The cost of 8 muffins and 2 quarts of milk is $18.

8m + 2q = 18

The cost of 3 muffins and 1 quart of milk is $7.50

3m + q = 7.5

So, we can solve the simultaneous equation

8m + 2q = 18

3m + q = 7.5

Solving this,

m = 1.5 dollars

q = 3 dollars

Hope this Helps!!!

3 0

1 year ago

Which equation represents the line that passes through the points (-3, 7) and (9,-1)? oy--3x+5 o y=-x-7 o y=zx-7 oy - 12 2x+5

olchik [2.2K]

Answer:

The answer is

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation we must first find the slope of the line.

So the slope of the line using points (-3, 7) and (9,-1) is

Now we use the formula

where

m is the slope

( x1 , y1) is any of the points given

So the equation of the line using point

( - 3 , 7) and slope - 2/3 is

We have the final answer as

Hope this helps you

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2 years ago

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Find the conjugate of the complex number, use division:<br> 2+i<br> ——<br> 1+i

Fittoniya [83]

I assume you mean divide using the conjugate to rationalize the denominator and express the result in standard rectangular form.

$\dfrac{2+i}{1+i} = \dfrac{2+i}{1+i} \cdot \dfrac{1-i}{1-i} = \dfrac{2(1)-i^2-2i+i}{1^2+1^2} = \frac 3 2 - \frac 1 2 i$

4 0

3 years ago

CAN ANYONE DO IT PLZ.

docker41 [41]

<u>Answer: </u>120

Since there is the 100 in the triangle, the other two sides in the triangle are equal to each other. So they are both 40

So 180 - 40 = 120

6 0

2 years ago

Read 2 more answers

Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -

GaryK [48]

Consider all parabolas:

$y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.$

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

$y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.$

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

$y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.$

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

$y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.$

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

$y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.$

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

$y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.$

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0

3 years ago