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2 years ago

SOMEONE PLS HELP the multiplicative inverse of 1/5 and (2x-1/5)

Mathematics

2 answers:

tigry1 [53]2 years ago

3 0

Answer:

You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.

Step-by-step explanation:

Brums [2.3K]2 years ago

3 0

Answer:

inverse 1/5 = (1/5)^-1

=1/(1/5)¹ = 1/(1/5) = 1(5/1) = 5/1 = 5

inverse 2x-1/5 = (2x-1/5)^-1

=1/(2x-1/5)¹ =1/(2x-1/5)

=1/(10x/5 - 1/5) = 1/(10x-1 / 5)

=1(5 / 10x-1) = 5 / 10x-1

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Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

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Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

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$x=\frac{2 \pm \sqrt{-16}}{2}$

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$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

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