Answer:
B: II, IV, I, III
Step-by-step explanation:
We believe the proof <em>statement — reason</em> pairs need to be ordered as shown below
Point F is a midpoint of Line segment AB Point E is a midpoint of Line segment AC — given
Draw Line segment BE Draw Line segment FC — by Construction
Point G is the point of intersection between Line segment BE and Line segment FC — Intersecting Lines Postulate
Draw Line segment AG — by Construction
Point D is the point of intersection between Line segment AG and Line segment BC — Intersecting Lines Postulate
Point H lies on Line segment AG such that Line segment AG ≅ Line segment GH — by Construction
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II Line segment FG is parallel to line segment BH and Line segment GE is parallel to line segment HC — Midsegment Theorem
IV Line segment GC is parallel to line segment BH and Line segment BG is parallel to line segment HC — Substitution
I BGCH is a parallelogram — Properties of a Parallelogram (opposite sides are parallel)
III Line segment BD ≅ Line segment DC — Properties of a Parallelogram (diagonals bisect each other)
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Line segment AD is a median Definition of a Median
A B D I’m pretty sure. Median is 3 or more and range just doesn’t make sense for 2 numbers
Answer:
and 4 easy
2
Step-by-step explanation:
For one and only 1 real solution, the discriminant = 0 (see chart attached)
<span>So we know b^2-4ac=0 when the equation is in the format of ax^2+bx-c=0. Make sure your equation is in the right format first!</span>
<span>Given kx^2+12x-4=0 </span>
<span>b=12 </span>
<span>so b^2-4ac=0 </span>
<span>144 = 4ac </span>
<span>144 = 4(k)(-4) </span>
<span>144/(-16) = k </span>
<span>k = -9</span>