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devlian [24]
3 years ago
9

Find the value of X in the diagram below.

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

The answer to your question is  x = 2

Step-by-step explanation:

Process

1.- Use proportions to solve this problem

          \frac{4x + 2}{23} = \frac{2x + 16}{23 + 23}

2.- Solve for x

                        46(4x + 2) = 23(2x + 16)

Expand

                        184x + 92 = 46x + 368

Simplify

                        184x - 46x = 368 - 92

                         138x = 276

                              x = 276/138

Result

                              x = 2

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Show you work! Giving lots of points for great explained answer!
Alja [10]

Answer:

If Kristen were to make 4 batches, and each batch requires 2 cups of flour, how many cups of flour would she need? To solve this question, we would just multiply 4 by 2, which gives us a final product of 8.

Similarly, in this question, if one batch requires 1 3/4 cups of flour and Kristen wants to bake 3 1/2 batches, she would need 1 3/4 x 3 1/2 cups of  flour.

1 3/4 can be rewritten as an improper fraction- 7/4.

3 1/2 can also be rewritten as an improper fraction- 7/2.

Multiplying 7/4 and 7/2, we obtain a final product of 49/8, or 6 1/8.

This means, Kristen will need 6 1/8 cups of flour to make 3 1/2 batches, and her belief that she needs 3 3/8 cups of flour is wrong, as she needs  a lot more than that.

Hope this helps!

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3 years ago
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Bryce has a rug that is 14 decimeters by 16 decimeters. Draw a sketch of Bryce'srug. Then find the area of his rug. Show your wo
yuradex [85]

Answer:

the answer is 224 decimeters

Step-by-step explanation:

first you need to draw a box than label the length and with which is 14 by 16 and then you can use the formula A=L*W. Know you can plug the numbers in 14*16 which equals 224 and that would be your answer

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Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

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Answer:

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Step-by-step explanation:

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