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4 years ago

Find the value of X in the diagram below.

Mathematics

1 answer:

Maru [420]4 years ago

4 0

Answer:

The answer to your question is x = 2

Step-by-step explanation:

Process

1.- Use proportions to solve this problem

$\frac{4x + 2}{23} = \frac{2x + 16}{23 + 23}$

2.- Solve for x

46(4x + 2) = 23(2x + 16)

Expand

184x + 92 = 46x + 368

Simplify

184x - 46x = 368 - 92

138x = 276

x = 276/138

Result

x = 2

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(199-55)/9= t
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3 years ago

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22 more than four times a number is less than 82 <br><br> (Inequality equation)

Tanzania [10]

22^4c-82. Is the equation I think you are looking for.

5 0

3 years ago

I really need help! it’s due soon:)

Stells [14]

Answer:

(5, 5), (7, 2), (3, 2)

Step-by-step explanation:

When reflecting a figure across the y-axis, the x value will be the opposite and the y value will remain the same

reflection across y-axis:

(x, y) ---> (-x, y)

Hope this helps!!

7 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

PLEASE HELP ASAP THANKS!

Vladimir [108]

Answer:

answer is 8$ have a great day

Step-by-step explanation: BRAINLIEST PLEASE

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3 years ago

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