Answer:
Roy is 10 years old at present and Joan is 5 years old at present
Step-by-step explanation:
Let
x----> Roy's age
y----> Joan's age
we know that
x=2y ----> equation A
(x+3)+(y+3)=21 ----> equation B
substitute equation A in equation B
(2y+3)+(y+3)=21
solve for y
3y+6=21
3y=21-6
3y=15
y=5 years
Find the value of x
x=2y ----> x=2(5)=10 years
therefore
Roy is 10 years old at present
Joan is 5 years old at present
14+2x=62 (x=Pass cost)
-14 -14
(2x=48)/2
x=24
6.50+5.75+1.15x=18
12.25+1.15x=18
-12.25 -12.25
1.15x=5.75 divide both sides by 1.15
x=5
Well, if we take 68.73 as the 100%, how much is 12 of it in percentage?
well

solve for "x"
Answer:
C. 20 feet
Step-by-step explanation:
Let x = width
Let y = length
If the length is at least 10 feet longer than the width:
⇒ x + 10 ≤ y
⇒ x ≤ y - 10
If the perimeter is to be no more than 100 ft:
⇒ 2x + 2y ≤ 100
⇒ x + y ≤ 50
⇒ x ≤ 50 - y
Equate the equations for x and solve for y:
⇒ y - 10 = 50 - y
⇒ 2y = 60
⇒ y = 30
Substitute found value of y into one of the inequalities for x:
⇒ x ≤ 30 - 10
⇒ x ≤ 20
Therefore, the maximum possible width of the fence is 20 feet.