3 years ago

Quadrilateral K' is the image of quadrilateral K under a dilation.

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

5 0

Answer:

C is the center of quadrilateral

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$\bf (\stackrel{x_1}{5}~,~\stackrel{y_1}{-8})\qquad
(\stackrel{x_2}{11}~,~\stackrel{y_2}{10})
\\\\\\
slope = m\implies
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$\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-(-8)=\cfrac{9}{8}(x-5)\implies y+8=\cfrac{9}{8}(x-5)
\\\\\\
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