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dlinn [17]
3 years ago
8

Quadrilateral K' is the image of quadrilateral K under a dilation.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

C is the center of quadrilateral

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What is the midpoint between the points (1, 4) and (-3, 2)?
emmasim [6.3K]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ -3}}\quad ,&{{ 2}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -3}} + {{ 1}}}{2}\quad ,\quad \cfrac{{{ 2}} + {{ 4}}}{2} \right)
6 0
4 years ago
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PLEASE PLEASE PLEASE HELP MEE!!!!!!!!!!!!!!!!
ivanzaharov [21]

Answer:

It is C

Step-by-step explanation:

5 0
3 years ago
Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX ​ is translated 4 units right and 3 uni
guapka [62]
Okay, so first of all, if the trapezoid was translated right 4,
Then all the (x)'s should be 4 more than the original value
For example: (2,-3) <span>→ (6,-3)
Now since the Trapezoid was translated down 3,
Then all the (y)'s should be 3 less than the original value
For example: (2,-3) </span><span>→ (2,-6)
Now do this to all the Vertices
</span>(6,-6)(8,-6)(9,-5)(5,-5)
Final Answer: <span>Option 2</span>
7 0
3 years ago
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Triangle ABC is transformed to triangle A'B'C', as shown below:
nordsb [41]

Answer:

<em>d). = m∠BCA = m∠B'C'A'</em>

Step-by-step explanation:

d). = m∠BCA = m∠B'C'A'

4 0
3 years ago
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The question is in the picture, PLEASE HELPPP!
Mumz [18]

Answer:

1=c

Step-by-step explanation:

1=c

2=d

3=e

4=a

5=b

I know 1 and 2 are correct, but I am not sure about the others

I'm not too sure how to explain this, sorry

8 0
3 years ago
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