Subtract z from the right side so that it becomes... u - z = vw
Then all you do is divide the right side of the equation(or equals sign) by w because your goal is to get whatever you're solving for by itself.
Your answer, then, is... u-z/w = v
Answer:
32.008
Step-by-step explanation:
Answer:
(0, e-1) or (0, 1.718) to the nearest thousandth.
Step-by-step explanation:
The y-intercept occurs when x = 0 so here we have:
y = e^(1 - 0) - 1
= e - 1
So the y-intercept is the point (0, e-1)
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

well then therefore

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )
