answer.
Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
5x+2y=105x+2y=10 (1)
And 3x+2y=63x+2y=6 (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
15x+6y=3015x+6y=30 (3)
15x+10y=3015x+10y=30 (4)
Now subtract (4) from (3) we get:
-4y=0−4y=0
y=0y=0
Now, put y=0 in (1) equation:
5x+2(0)=105x+2(0)=10
5x=105x=10
x=2x=2
Hence, x=2 and y=0
<h2>
Answer:</h2>
<u>The answer is </u><u>(C) 4</u>
<h2>
Step-by-step explanation:</h2>
According to the rule of BODMAS
We will first do division then Multiplication then addition and in the last we do subtraction
So
12 ÷ 2 + 4 – 2 × 3 will be done as
= (12 ÷ 2) + 4( – 2 × 3)
= 6+4-6
= 4
