The man's transport cost is Rs 4800
Step-by-step explanation:
- Step 1: Given that the amount the man spent on food = Rs 16800 which is 42% of his salary. Form an equation where his salary is x.
42% of x = 16800
42/100 × x = 16800
42x = 1,680,000
x = 1,680,000/42 = Rs 40,000
∴ Salary is Rs 40,000
- Step 2: Calculate the man's transport cost.
12% of 40000 = 12/100 × 40000 = Rs 4800
Substitute x with the members of the domain.
f(x) = 5x² + 4
Substitute with the domain of -4
f(x) = 5x² + 4
f(-4) = 5(-4)² + 4
f(-4) = 5(16) + 4
f(-4) = 80 + 4
f(-4) = 84
Substitute with the domain of -2
f(x) = 5x² + 4
f(-2) = 5(-2)² + 4
f(-2) = 5(4) + 4
f(-2) = 20 + 4
f(-2) = 24
Substitute with the domain of 0
f(x) = 5x² + 4
f(0) = 5(0)² + 4
f(0) = 5(0) + 4
f(0) = 0 + 4
f(0) = 4
Substitute with the domain of 1.5
f(x) = 5x² + 4
f(1.5) = 5(1.5)² + 4
f(1.5) = 5(2.25) + 4
f(1.5) = 11.25 + 4
f(1.5) = 15.25
Substitute with the domain of 4
f(x) = 5x² + 4
f(4) = 5(4)² + 4
f(4) = 5(16) + 4
f(4) = 80 + 4
f(4) = 84
The range of the function for those domain is {4, 24, 15.25, 84}
