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Gala2k [10]
3 years ago
5

The original price of a pair of jeans is $32 the sales price 15% off the original price what is the amount off the original pric

e
Mathematics
1 answer:
ivolga24 [154]3 years ago
3 0

$32+15%=32.15

Hope this helps ^_^

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What is x and measure b? please help:)
BARSIC [14]

Answer: x= 22.5, angle B = 67.5

Step-by-step explanation:

90+3x+x= 180

4x = 90

x=22.5

3(22.5)= 67.5

5 0
2 years ago
Read 2 more answers
Type the correct answer for each.
xxTIMURxx [149]
If point \left(x,\ \frac{\sqrt{7}}{3}\right) is on the unit ircle, then:

x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\  \\ \Rightarrow x^2+ \frac{7}{9} =1 \\  \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9}  \\  \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}

Since, the point is in the second quadrant, x is negative.

Thus, (x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)

Part A:

3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\  \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\  \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\  \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta

Therefore, -6\tan\theta=3\sqrt{7}.



Part B:

- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} }  \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x}  \\  \\ =\tan\theta

Therefore, \tan\theta=- \frac{ \sqrt{7} }{2}
8 0
3 years ago
Write an inequality that represents eight less than 3 times a number is more than 22​
SCORPION-xisa [38]

Answer:

3x-8>22

Step-by-step explanation:

3 times a number = 3x

8 less = -8

more than 22 = >22

Put them together and you get:

3x-8>22

8 0
2 years ago
Augusto has a rectangular garden that is 11 feet wide. The length of the diagonal is 1 foot greater than the length of the garde
brilliants [131]
The answer is C
call the length is a => the diagonal is a+1
11^2 + a^2=(a+1)^2
<=> 121 + a^2=a^2 + 2a +1
<=>120=2a
<=> a=60
5 0
3 years ago
If the mean of 5 positive integers is 15, what is the maximum possible difference between the largest and the smallest of these
Vikki [24]

Answer:

if the 5 numbers are different, the maximum difference is 64

Step-by-step explanation:

We have 5 positive (different) integers, a, b, c, d and e (suppose that are ordered from least to largest, so a is the smallest and b is the largest.

The mean will be:

M = (a + b + c + d + e)/5 = 15.

Now, if we want to find the largest difference between a and e, then we must first select the first 4 numbers as the smallest numbers possible, this is:

a = 1, b = 2, c = 3 and d = 4

M = (1 + 2 + 3 + 4 + d)/5 = 15

M = (10 + d)/5 = 15

10 + d = 15*5 = 75

d = 75 - 10 = 65

then the difference between a and d is = 65 - 1 = 64.

Now, if we take any of the first 4 numbers a little bit bigger, then we will see that the value of d must be smaller, and the difference between d and a will be smaller.

5 0
2 years ago
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