We want to find the probability that the two students chosen for the duet are boys. We will find that the probability that both students chosen for the duet are boys is 0.458
If we assume that the selection is totally random, then all the students have the same<em> </em><em>probability </em><em>of being chosen.</em>
This means that, for the first place in the duet, the probability of randomly selecting a boy is equal to the quotient between the number of boys and the total number of students, this is:
P = 11/16
For the second member of the duet we compute the probability in the same way, but this time there is one student less and one boy less (because one was already selected).
Q = 10/15
The joint probability (so both of these events happen together) is just the product of the individual probabilities, this will give:
Probability = P*Q = (11/16)*(10/15) = 0.458
So the probability that both students chosen for the duet are boys is 0.458
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Answer:
--- Objective function
Interval = 
Step-by-step explanation:
Given
Represent the number with x
The required sum can be represented as:
Hence, the objective function is:
To get the the interval, we start by differentiating w.r.t x
<em>Using first principle, this gives:</em>
Equate S'(x) to 0 in order to solve for x
Subtract 1 from both sides
Multiply both sides by -1
Cross Multiply
Take positive square root of both sides because x is positive
Representing x using interval notation, we have
Interval =
To get the smallest sum, we substitute 1 for x in
<em>Hence, the smallest sum is 2</em>
Answer:
Yes
Step-by-step explanation:
32 divided by 45 = .7111111111111111111
to go from point to point
we go up six units and to the right 1 unit
slope = 6/1
m = 6
