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igomit [66]
3 years ago
8

There is a bag with only milk and dark chocolates. The probability of randomly choosing a dark chocolate is 3 8 . There are 21 d

ark chocolates in the bag and each is equally likely to be chosen. Work out how many milk chocolates there must be.
Mathematics
1 answer:
aliina [53]3 years ago
6 0

Answer:

Number of milk chocolate in beg = 56

Step-by-step explanation:

Given:

Probability of randomly choosing a dark chocolate = 3/8

Number of dark chocolate = 21

Find:

Number of milk chocolate in beg

Computation:

Number of milk chocolate in beg = Number of dark chocolate / Probability of randomly choosing a dark chocolate

Number of milk chocolate in beg = 21 / [3/8]

Number of milk chocolate in beg = 21[8/3]

Number of milk chocolate in beg = 7[8]

Number of milk chocolate in beg = 56

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What term best describes 3y – 5?
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B

Step-by-step explanation:

Because you have to solve for the variable, making it algebraic.

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3 years ago
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4 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

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3 years ago
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