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nexus9112 [7]
3 years ago
6

What is the slope of the line that passes through the two given points? (13, -2) and (3, -2)

Mathematics
1 answer:
Zolol [24]3 years ago
5 0

Answer:

the \: slope \: is \:  \boxed{0}

Step-by-step explanation:

the \: slope \:  : m = \frac{  - 2 - ( - 2)}{3 - 13}  = -   \frac{0}{10}

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What's is the converse of the statement?If x is odd, then 2x is even.
dsp73
If you have two statements p and q and p\Rightarrow q is true, then  \neg q\Rightarrow \neg p is also true.

In your case, statements are p - "x is odd" and q -  "2x is even".

 Then \neg p - "x is not odd" and \neg q - "2x is not even."


Hence \neg q\Rightarrow \neg p sounds as: "If 2x is not even, then x is not odd".
Answer: correct choice is D.







7 0
3 years ago
Mr. Carandang sold a total of 1,790 prints of one of his drawings. Out of all 1,273 unframed prints that he sold, 152 were small
vlada-n [284]

Answer: 517

Step-by-step explanation:

8 0
2 years ago
Find the area of △LKJ.
nirvana33 [79]

Answer:

A=600\: u^{2}

<u>The correct answer is letter c.</u>

Step-by-step explanation:

The area equation of a triangle is given by:

A=\frac{bh}{2}  (1)

Where:

b is the base

h is the height

Let's find first the angle MJK (α), using the tangent definition.

tan(\alpha)=\frac{24}{32}

\alpha=tan^{-1}(\frac{24}{32})

\alpha=36.9^{\circ}

Now, if α = 37° then β (angle JLK) must be:

37^{\circ} + \beta + 90^{\circ}=180^{\circ}

\beta=53^{\circ}

Now, we can find the distance ML using again the tangent definition:

tan(\beta)=\frac{24}{ML}

ML=\frac{24}{tan(53)}

ML=18

The base of the triangle LKJ will be:

b=32+ML=32+18=50

Therefore, using equation (1) the area of △LKJ will be:

A=\frac{50*24}{2}

A=600\: u^{2}

The correct answer is c.

I hope it helps you!

5 0
3 years ago
3^-1 ___ 1/4 <br> a &gt; <br> b &lt; <br> c =
Readme [11.4K]

Answer:

a ">"

Step-by-step explanation:

3 to the power negative one (-1) is the same as 1/3 (one unit divided by 3).

1/4 on the other hand is one unit divided by 4.

Dividing one object into three parts (think for example a chocolate bar) gives you a larger (greater) piece than dividing it into four equal pieces.

Therefore 1/3  > 1/4

8 0
3 years ago
Which postulate or theorem can be used to prove that AABC = ADCB?<br> SSS<br> ASA<br> SAS<br> AAS
koban [17]
<h3>Answer : </h3>

SSS congruency criteria can be used here to prove ∆ABC ≅ ∆DCB

<h3>Solution : </h3>

In ∆ABC and ∆DCB

AB = CD (given)

AC = BD (given)

BC = BC (common)

So, by SSS congruency criteria,

∆ABC ≅ ∆DCB

6 0
2 years ago
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