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lions [1.4K]
3 years ago
8

Divide. Use​ place-value blocks or area models to help.

Mathematics
1 answer:
Shalnov [3]3 years ago
5 0

Answer:

a 5,900÷90=65.5555555556

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What is numbers line x<8
drek231 [11]

Answer:

I cant draw it perfectly so please dont judje if it not helpful

Step-by-step explanation:

x<------------------------------------->infinity

So put a dot at the arrow pointing to X and then trace the line and the arrow to infinity dark.

7 0
3 years ago
7/8 - 1/4 - 1/2= ??
madreJ [45]

Step-by-step explanation:

We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.

Cheers!

7 0
2 years ago
-7x + (-3x) + (-x)= how do i solve this
viva [34]

Answer:

-11x

Step-by-step explanation:

-7x + (-3x) + (-x)

= -7x - 3x - x

=-11x

3 0
3 years ago
Given that m/_a=40 and m/_b=61 find that the measure of angles x and y
brilliants [131]
Answer:
y = 140, x = 159
Step-by-step explanation:
Angle y:
we can find this angle by subtracting 40 from 180, 180-40 = 140 = y
Angle x:
Some measure of an angle plus angle b is equal to 180 degrees: 180-61 = 119
We can now find the measure of the third angle of the triangle: 180-(119+40) = 21
The third angle plus angle x is equal to 180: 180-21 = 159 = x
7 0
1 year ago
Read 2 more answers
Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
3 years ago
Read 2 more answers
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