Answer:
FE = 30°
Step-by-step explanation:
arc FGC = arc FG + arc GB + arc BC
220° = 90° + arc GB + 70° . . substitute known values
60° = arc GB . . . . . . . . . . . . . subtract 160°
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External angle A is half the difference of arcs EG and GB:
30° = (1/2)(arc FE +90° -60°) . . . substitute known values
60° = arc FE + 30° . . . . . . . . . . . multiply by 2 and simplify
30° = arc FE . . . . . . subtract 30°
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The key to this problem is the relationship between external angle A and the measures of the arcs it subtends.
Answer:
Step 2 shows Emily's first mistake.
Step-by-step explanation:
3(2) = 6
But instead of this Emily wrote 3(2) = 9.
Answer:
Domain: [-3, 5]
Range: [-5, 4]
Step-by-step explanation:
The first thing is to define what is the domain and the range. The domain of a function f (x) is the set of all the values for which the function is defined, and the range of the function is the set of all the values that f takes.
In other words, the domain is the value on the "x" axis and the range is the value on the "y" axis.
In this case, both are an interval, the domain would be from -3 to 5 and in the case of the range it would be from -5 to 4.
Domain: [-3, 5]
Range: [-5, 4]
He will need to save for 40 weeks
Answer:
x=8
RPS = 36
Step-by-step explanation:
QPS = 180
The two angles that form QPS
QPR + RPS = 180
7x+88 + 3x+12 = 180
Combine like terms
10x+100 =180
Subtract 100 from each side
10x = 180-100
10x = 80
Divide by 10
x =80/10
x = 8
RPS = 3x+12
= 3(8)+12
24+12
36
