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kompoz [17]
3 years ago
12

Assume one individual from the group is randomly selected. Find the probability of getting someone who tests negative​, given th

at he or she had the disease. the probability is approximately?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

P(Negative | Yes) = 0.0486

Step-by-step explanation:

Given

\begin{array}{ccc}{} & {Yes} & {No} & {Positive} & {137} & {24} & {Negative} & {7} & {132} \ \end{array}

Required

P(Negative | Yes)

This is calculated as:

P(Negative | Yes) = \frac{n(Negative\ n\ Yes)}{n(Yes)}

So, we have:

P(Negative | Yes) = \frac{7}{137+7}

P(Negative | Yes) = \frac{7}{144}

P(Negative | Yes) = 0.0486

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Answer:

The values of x and y are x = 6 and y = 9Step-by-step explanation:

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In any parallelogram diagonals:

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Meet each other at their mid-point

In parallelogram MNOP

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∵ MO intersect NP at point A

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