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kompoz [17]
3 years ago
12

Assume one individual from the group is randomly selected. Find the probability of getting someone who tests negative​, given th

at he or she had the disease. the probability is approximately?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

P(Negative | Yes) = 0.0486

Step-by-step explanation:

Given

\begin{array}{ccc}{} & {Yes} & {No} & {Positive} & {137} & {24} & {Negative} & {7} & {132} \ \end{array}

Required

P(Negative | Yes)

This is calculated as:

P(Negative | Yes) = \frac{n(Negative\ n\ Yes)}{n(Yes)}

So, we have:

P(Negative | Yes) = \frac{7}{137+7}

P(Negative | Yes) = \frac{7}{144}

P(Negative | Yes) = 0.0486

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Help! in 20P9 what does the 9 represent?
Alex777 [14]

Answer:

Step-by-step explanation:

Good question. It is important to know the answer.  

The 9 means that there are a total of 20 objects. You want to select just 9 of them.

The situation is well described by C.

6 0
3 years ago
What is the completely simplified equivalent of 2/(5+i)?
Bezzdna [24]

namely, let's rationalize the denominator in the fraction, for which case we'll be using the <u>conjugate</u> of that denominator, so we'll multiply top and bottom by its <u>conjugate</u>.

so the denominator is 5 + i, simply enough, its conjugate is just 5 - i, recall that same/same = 1, thus (5-i)/(5-i) = 1, and any expression multiplied by 1 is just itself, so we're not really changing the fraction per se.

\bf \cfrac{2}{5+i}\cdot \cfrac{5-i}{5-i}\implies \cfrac{2(5-i)}{\stackrel{\textit{difference of squares}}{(5+i)(5-i)}}\implies \cfrac{2(5-i)}{\stackrel{\textit{recall }i^2=-1}{5^2-i^2}}\implies \cfrac{2(5-i)}{25-(-1)} \\\\\\ \cfrac{2(5-i)}{25+1}\implies \cfrac{2(5-i)}{26}\implies \cfrac{5-i}{13}

4 0
3 years ago
In football seasons, a team gets 3 points for a win, 1 point for a draw and 0 points for a
Dvinal [7]

Answer:

The difference between the games won and lost = 21 - 6 =15

Step-by-step explanation:

According to the question In a football season a team gets 3 points for a win, 1 point for a draw and 0 points for a loss.

A particular season a team played 34 games and lost 6 games . Finding the difference between game won and game lost simply means we have to know the number of game lost and game won.

The team played a total of 34 games.

Total games played = 34

Out of the 34 games played they lost 6 games. That means the remaining games is either win or draw. Therefore,

34 - 6 = 28 games was won or draw

Let

the number of games won = x

the number of game drew = y

3x + y = 70.............(i)

x  + y = 28................(ii)

x = 28 - y

insert the value of x in equation(i)

3(28 - y) + y = 70

84 - 3y + y = 70

84 - 70 = 3y -y

14 = 2y

divide both sides by 2

y = 14/2

y = 7

insert the value of y in equation(ii)

x + y = 28

x = 28 - 7

x = 21

The team won 21 games , drew 7 games and lost 6 games.

The difference between the games won and lost = 21 - 6 =15

3 0
3 years ago
What is the answer I'm having trouble?4(2t+6)=
Galina-37 [17]
4(2t+6)

8t+24 is the answer

4 0
2 years ago
Read 2 more answers
PLEASE HELP I JUST NEED THE ANSWER NOT AN EXPLANATION TO HOW YOU GOT THE ANSWER
Yuki888 [10]

The answer is b, > because 30.17 is bigger than 30.018

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2 years ago
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