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yuradex [85]
3 years ago
9

Find the volume of a pyramid with a square base, where the side length of the base is 16 in16\text{ in} 16 in and the height of

the pyramid is 22.1 in22.1\text{ in} 22.1 in. Round your answer to the nearest tenth of a cubic inch.
Mathematics
1 answer:
guapka [62]3 years ago
3 0

<u>Given</u>:

Given that the side length of the base of the square pyramid is 16 inches.

The height of the pyramid is 22.1 inches.

We need to determine the volume of the square pyramid.

<u>Volume of the square pyramid:</u>

The volume of the square pyramid can be determined using the formula,

V=\frac{1}{3}Bh

where B is the area of the base and h is the height of the pyramid.

Substituting B = (16 × 16) and h = 22.1, we get;

V=\frac{1}{3}(16 \times 16)(22.1)

V=\frac{1}{3}(256)(22.1)

V=\frac{1}{3}(5657.6)

V=1885.9

Thus, the volume of the pyramid is 1885.9 cubic inches.

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Answer:

The answer is 7 2/3 cans for the next 6 days.

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Given: The dog ate 50 cans in 30 days.

To get how many cans per day, divide:

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To get how many cans for 6 days, multiply:

6 * 1 2/3 = 18/3 + 5/3 = 23/3 = 7 2/3 cans or 7.667 in decimal form.

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3 years ago
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julsineya [31]

Answer:

Step-by-step explanation:

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2 years ago
Mark invests $6,700 in an online savings account which gives 4.2% simple annual interest. He also invests $6,000 in a savings ac
dalvyx [7]

Answer:

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Step-by-step explanation:

Calculation:

First, converting R percent to r a decimal

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Calculation:

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5 0
3 years ago
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adelina 88 [10]

Answer:

L = 10(\frac{1}{2} )^{t-4}

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If t is the number of days since Sofia took the medication of 10 mg, then the amount of medication in her system after t days will be S = 10(\frac{1}{2} )^{t}.

So, the concentration of medicine in blood decreases by a factor of one half every day.

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3 years ago
Read 2 more answers
Use substitution to solve the following system of linear equations and fill in the following blanks:
marissa [1.9K]

Answer:

x=-4

y=3

z=-5

Step-by-step explanation:

<u>Given:</u>

x+y+z=-6

x-6y-7z=-29

-7y-5z=4

<u>Solve for </u>x<u> in the 1st equation:</u>

x+y+z=-6

x+y=-z-6

x=-y-z-6

<u>Substitute the value of </u>x<u> into the 2nd equation and solve for </u>z<u>:</u>

x-6y-7z=-29

(-y-z-6)-6y-7=-29

-7y-z-13=-29

-7y-z=-16

-z=-16+7y

z=16-7y

<u>Substitute the value of </u>z<u> into the 3rd equation and solve for </u>y<u>:</u>

-7y-5z=4

-7y-5(16-7y)=4

-7y-80+35y=4

28y-80=4

28y=84

y=3

<u>Plug </u>y=3<u> into the solved expression for </u>z<u> and evaluate to solve for </u>z<u>:</u>

z=16-7(3)

z=16-21

z=-5

<u>Plug </u>z=-5<u> into the solved expression for </u>x<u> and evaluate to solve for </u>x<u>:</u>

x=-(3)-(-5)-6

x=-3+5-6

x=2-6

x=-4

Therefore:

x=-4

y=3

z=-5

6 0
3 years ago
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