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goldenfox [79]
3 years ago
12

HELP ASAP Simplify the following polynomial expression. The polynomial simplifies to an expression that is a ____ _______ with a

degree of ___.

Mathematics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

The polynomial simplifies to an expression that is a  

quadratic  trinomial  with a degree of  2 .

Step-by-step explanation:

trial and error

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Alicia wants to bake a cake with ⁹/10 grams of flour.However,she only has ⅓ grams of flour she needs.How much does she have?
natali 33 [55]

Answer:

We know that:

She needs 9/10 grams of flour for the cake (this quantity does not make a lot of sense, maybe is written incorrectly, but is the only info we have, so let's solve the problem with this)

She only has 1/3 of the amount she needs.

How much flour does she have?

Well, she needs 9/10 grams, and she has one-third of that.

Then she has (1/3) times (9/10) grams, this is:

F = (1/3)*(9/10) grams

F = (1*9)/(3*10) grams

F = 9/30 grams

That is the amount of flour that she has.

6 0
3 years ago
What is the area of a square 11cm and 15cm
Veronika [31]
To find the area you times length times width give you the area so 11 X 15 is 165cm squered
8 0
4 years ago
a painter rented a wallpaper steamer at 9am and returned it at 4pm. he paid a total of 28.84. what was the rental cost per hour?
jolli1 [7]
The total number of hours was 7 so divide $28.84 by 7 and you'll get $4.12 per hour.
4 0
3 years ago
Read 2 more answers
After *triangle* ACE is dilated by a factor of 5, It has an area of 100 square inches. What was its area before dilation?
Anarel [89]
<h3>Answer:  4 square inches</h3>

Explanation:

Square the linear scale factor to get 5^2 = 25

This means that,

new area = 25*(old area)

We take this idea in reverse to find the old area

old area = (new area)/25

old area = (100 sq inches)/25

old area = 4 square inches

6 0
3 years ago
Is it all right and I need help on EVALUATE EXPRESSIONS. PLZ help me
taurus [48]

(1)   12,    (2)   5,    (3)   13,    (4)    30

Step-by-step explanation:

(1) Given expression 2x.

Substitute x = 6 in expression 2x.

⇒ 2 × 6 = 12

(2) Given expression 8 + 3 – x

Substitute x = 6 in expression 8 + 3 – x.

⇒ 8 + 3 – 6 = 11 – 6 = 5

(3) Given expression 6 + 7 – 6 + x

Substitute x = 6 in expression 6 + 7 – 6 + x.

⇒ 6 + 7 – 6 + x = 6 + 7 – 6 + 6 = 13

(4) Given expression 5x

Substitute x = 6 in expression 5x.

⇒ 5× 6 = 30

4 0
3 years ago
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