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2 years ago

Alicia wants to bake a cake with ⁹/10 grams of flour.However,she only has ⅓ grams of flour she needs.How much does she have?

Mathematics

1 answer:

natali 33 [55]2 years ago

6 0

Answer:

We know that:

She needs 9/10 grams of flour for the cake (this quantity does not make a lot of sense, maybe is written incorrectly, but is the only info we have, so let's solve the problem with this)

She only has 1/3 of the amount she needs.

How much flour does she have?

Well, she needs 9/10 grams, and she has one-third of that.

Then she has (1/3) times (9/10) grams, this is:

F = (1/3)*(9/10) grams

F = (1*9)/(3*10) grams

F = 9/30 grams

That is the amount of flour that she has.

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What is the area of this figure? Please help.

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The area of the composite figure can be found by summing the whole area that made up the figure. Therefore, the area of the figure is 213.5m²

<h3>Area of a composite figure</h3>

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Hence,

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2 years ago

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3 years ago

Read 2 more answers

∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are

son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

In ΔABC

∴ The congruent sides are AB and AC respectively

CB =12 ft. 4 in.=148 in.
AB= $\frac{3}{4}$ CB =111 in. =9 ft. 3 in.
AC= $\frac{3}{4}$ CB =111 in. =9 ft. 3 in.

∵ <em>Perimeter of ΔABC</em> =AB+AC+CB

=9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

=30 ft. 10 in.

2. In ΔDEF

∴ The congruent sides are DE and DF respectively

DE = 6 ft. 3 in. =75 in.
DF = 6 ft. 3 in. =75 in.
Let the length of FE is equal to x
0.75FE =DE =DF
0.75x = 6 ft. 3 in. =75 in.
x =100 in. =8 ft. 4 in.

∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

= 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

= 20 ft. 10 in.

3. In ΔJKL

∴ The congruent sides are JL and KL respectively

JK = x+3
KL =4x-17
JL =6x-45
JL≅KL
4x-17 =6x-45 . . . . . . . . . . . . . . . . . . . . . . . (1)
Subracting 4x from both sides from eq 1
-17 =2x-45
Adding 45 on both the sides
28 =2x
Dividing by 2 on both sides
14 =x
JK = 14+3 =17
KL = 4×14-17 =39
JL = 6×14-45 =39

∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

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