Option A. is correct for the given condition.
Lets solve it through steps of range and functions,
First of all, Solve the equation:

(1)
(2)
So these would be the ranges of X in between 5 and -5.
Hence option A.
is correct.
Learn more about range and functions on:
https://brainly.ph/question/10400053
#SPJ10
Answer:
f(12) = - 20
Step-by-step explanation:
To evaluate f(12), substitute x = 12 into f(x), that is
f(12) = - 2(12) + 4 = - 24 + 4 = - 20
Eight *(a number) plus 5*(another number) is -13.
translates to:
8(x) + 5(y) = -13
The sum of (the number) and (the other number) is 1.
translates to:
(x) + (y) = 1
We have a system of two equations involving two unknowns: x and y.

We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.
We'll multiply the second equation by -8 so that the x's match up.

When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.

Divide by -3,

Plug back into one of your original equations to find the value of x,

Subtract 7,
Answer:
<em>The volume of the cube is </em>
<em>cu in.</em>
Step-by-step explanation:
<u>The Volume of a Cube</u>
Let's have a cube of side length a. The volume of the cube is:

The cube of the image has a side length of

Simplifying the expression of the base by converting the negative exponent in the numerator to the denominator:

Now find the volume:

Applying the exponents:


The volume of the cube is
cu in.
We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)