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2 years ago

After triangle ACE is dilated by a factor of 5, It has an area of 100 square inches. What was its area before dilation?

Mathematics

1 answer:

Anarel [89]2 years ago

6 0

<h3>Answer: 4 square inches</h3>

Explanation:

Square the linear scale factor to get 5^2 = 25

This means that,

new area = 25*(old area)

We take this idea in reverse to find the old area

old area = (new area)/25

old area = (100 sq inches)/25

old area = 4 square inches

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Help please<br> what is<br>

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

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2 years ago

Find the value of f(12) if f(x)=-2x+4

Contact [7]

Answer:

f(12) = - 20

Step-by-step explanation:

To evaluate f(12), substitute x = 12 into f(x), that is

f(12) = - 2(12) + 4 = - 24 + 4 = - 20

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3 years ago

Eight times a number plus five another number is -13. The sum of the two numbers is 1. What are the numbers?

Pani-rosa [81]

Eight *(a number) plus 5*(another number) is -13.

translates to:

8(x) + 5(y) = -13

The sum of (the number) and (the other number) is 1.

translates to:

(x) + (y) = 1

We have a system of two equations involving two unknowns: x and y.

$\rm 8x+5y=-13\\
~~x+~~y=~~~~1$

We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.

We'll multiply the second equation by -8 so that the x's match up.

$\rm ~~~8x+5y=-13\\ -8x-8y=-8$

When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.

$\rm -3y=-21$

Divide by -3,

$\rm y=7$

Plug back into one of your original equations to find the value of x,

$\rm x+y=1\\
x+7=1$

Subtract 7,

$\rm x=-6$

8 0

3 years ago

Please help, I I beg you please

Tatiana [17]

Answer:

<em>The volume of the cube is </em> $\mathit{\frac{27}{z^3x^{9}}}$ <em>cu in.</em>

Step-by-step explanation:

<u>The Volume of a Cube</u>

Let's have a cube of side length a. The volume of the cube is:

$V=a^3$

The cube of the image has a side length of

$\displaystyle a=\frac{3x^{-3}}{z}\ inches$

Simplifying the expression of the base by converting the negative exponent in the numerator to the denominator:

$\displaystyle a=\frac{3}{zx^{3}}\ inches$

Now find the volume:

$\displaystyle V=\left(\frac{3}{zx^{3}}\ inches\right)^3$

Applying the exponents:

$\displaystyle V=\frac{3^3}{z^3x^{9}}\ inches^3$

$\displaystyle V=\frac{27}{z^3x^{9}}\ inches^3$

The volume of the cube is $\mathbf{\frac{27}{z^3x^{9}}}$ cu in.

8 0

3 years ago

Frank cut a 52 inch string into 3 pieces. The first piece is 20 inches long. The second piece is at least 12 inches long, but no

Eddi Din [679]

We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.

The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)

So we can say that x is greater or equal to 14, but less than or equal to 20, or:

14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)

4 0

3 years ago

After *triangle* ACE is dilated by a factor of 5, It has an area of 100 square inches. What was its area before dilation?

After triangle ACE is dilated by a factor of 5, It has an area of 100 square inches. What was its area before dilation?