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GalinKa [24]
4 years ago
8

Describe transformation y=(x+5)^2 -19

Mathematics
1 answer:
Nana76 [90]4 years ago
6 0

Answer:

y=x^2 +10x+6 should be the answer

Step-by-step explanation:

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Staci is attending a music festival. The ticket to the festival costs $87.96 . Staci plans to purchase $30.00 t-shirts form the
d1i1m1o1n [39]

Answer:

3 t-shirts

Step-by-step explanation:

<u>Lets recap the information we will use from this problem:</u>

The ticket to the festival costs $87.96

T-shirts are $30.00

She is taking $200.00 to the festival

Now we can solve. First we will subtract the price of the ticket from the total amount of money she has.

$200.00 - $87.96 = $112.04

Now that she has payed for the ticket, we want to find out how many shirts she can buy with the remainder of her money. To find this, we will set up an equation like this:

(Amount of money left) ÷ (Cost of 1 t-shirt) = (How many t-shirts she can buy)

Insert your numbers: $112.04 ÷ $30.00 = 3.73466666667

Because she cant buy a fraction of a t-shirt, we ignore the decimals on the end of this number. Therefore, Staci can purchase 3 t-shirts.

5 0
3 years ago
Find the equation of the lines parallel and perpendicular to the line 5x+2y=12 through the point (-2,3)
muminat

Answer:

The equation of line parallel to given line and passing through points        ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Step-by-step explanation:

Given equation of line as :

5 x + 2 y = 12

or, 2 y = - 5 x + 12

or , y = \frac{-5}{2} x + \frac{12}{2}

Or, y = \frac{-5}{2} x + 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = \frac{-5}{2}

Again,

The other line if passing through the points (- 2 , 3 ) And  is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So,  M = m = \frac{-5}{2}

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M x + c

Now , satisfying the points

So, 3 = \frac{-5}{2} × ( - 2 ) + c

or, 3 =  \frac{10}{2} + c

Or, 3 = 5 + c

∴  c = 3 - 5 = - 2

c = - 2

So, The equation of line with slope  \frac{-5}{2}  and passing through points ( -2 , 3)

y =  \frac{-5}{2} x - 2

or, 2 y = - 5 x - 4

I.e 5 x + 2 y + 4 = 0

<u>Similarly</u>

The other line if passing through the points (- 2 , 3 ) And  is perpendicular  to given line

So, for perpendicular lines condition,the products of slope of both lines = - 1

Let The slope of other line = M'

So,  M' × m = - 1

Or, M' ×  \frac{-5}{2} = - 1

Or, M' = \frac{-1}{\frac{-5}{2}}

Or, M' =  \frac{2}{5}

∴ The equation of line with slope M and passing through points ( -2 , 3) is

y = M' x + c'

Now , satisfying the points

So, 3 = \frac{2}{5} × ( - 2 ) + c'

or, 3 =  \frac{- 4}{5} + c'

Or, 3 × 5 = - 4 + 5× c'

∴  5 c' = 15 + 4

or, 5 c' = 19

Or, c' =  \frac{19}{5}

So, The equation of line with slope  \frac{2}{5}  and passing through points ( -2 , 3)

y =  \frac{2}{5} x +  \frac{19}{5}

y =  \frac{2 x + 19}{5}

Or, 5 y = 2 x + 19

Or, 2 x - 5 y + 19 = 0

Hence The equation of line parallel to given line and passing through points ( - 2 , 3 ) is 5 x + 2 y + 4 = 0

And  The equation of line perpendicular to given line and passing through points ( - 2 , 3 ) is 2 x - 5 y + 19 = 0

Answer

4 0
3 years ago
What is the actual length of the microchip?
RideAnS [48]

Answer:

12 millimeters is the actual length of a microchip

8 0
3 years ago
Rewrite without absolute value for the given condition: y=|x−3|+|x+2|−|x−5|, if 3 &lt; x &lt; 5
natka813 [3]

Answer:

x>3 but x<5 so x=4

4-3=1

+

4+2=6

-

4-5=-1

but |-1|=1

so

1+6-1=6

8 0
3 years ago
Y=1/4 (x+2)(x – 6
gladu [14]
I have no idea I’m answering this because I need to ask more questions
4 0
3 years ago
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