(3x−2)(2x^2+5)
=(3x+−2)(2x^2+5)
=(3x)(2x^2)+(3x)(5)+(−2)(2x^2)+(−2)(5)
=6x^3+15x−4x^2−10
=6x^3−4x^2+15x−10
Answer:
Step-by-step explanation:
value of 4, and you want to square it or exponent 2
so 4^2 = 4x4
=16
What is ^-2
It does the same operation however because to is negative it really means putting 4 in the denominator so 2 becomes positive. Inverse of the exponent 2
1/4^2 is the same as 4^-2
which will both give 1/16
24. To find the mean add all of the numbers and divide the sum by the number of digits you added. Meaning that you would add 25, 15, 18, 20, 87, 13, 8, 22, and 14 which is 240 and divide that by 10 since there are 10 numbers. Hope that this helped, have a blessed day :)
Answer:
The answer is below
Step-by-step explanation:
Given the system of equations:
x + y + 2z = 9
2x + 4y - 3z = 1
3x + 6y - 5z = 0
This system of equation can be solved using matrix. This done by first representing the equations as matrix and then solving:
The matrix form is:
![\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&2\\2&4&-3\\3&6&-5\end{array}\right] ^{-1} \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%262%5C%5C2%264%26-3%5C%5C3%266%26-5%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%262%5C%5C2%264%26-3%5C%5C3%266%26-5%5Cend%7Barray%7D%5Cright%5D%20%20%5E%7B-1%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C)
![\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2&-17&11\\-1&11&-7\\0&3&-2\end{array}\right] \left[\begin{array}{c}9\\1\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}1\\2\\3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-17%2611%5C%5C-1%2611%26-7%5C%5C0%263%26-2%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1%5C%5C2%5C%5C3%5Cend%7Barray%7D%5Cright%5D)
Answer:
14 cm.
Step-by-step explanation:
We have been given that an aquarium is a right rectangular prism 18.5 cm long and 15 cm wide. We are also told that Martene put 3885 cubic cm of water in the aquarium.
To find the depth or height of aquarium, we will use volume of rectangular prism formula.
, where,
l = Length of prism,
w = Width of prism,
h = Height of prism.
Upon substituting our given values in above formula we will get,




Therefore, the aquarium is 14 cm deep.