4/5(v - 7) = 2...distribute the 4/5 thru the parenthesis
4/5v - 28/5 = 2 ...multiply everything by 5
4v - 28 = 10...add 28 to both sides
4v = 10 + 28
4v = 38
v = 38/4 reduces to 19/2 or 9 1/2 <==
Answer: see Explanation
Step-by-step explanation:
THE GAINEY'S:
Recursive Formula :
A1 = $10
An = An-1 + $10
A2 = $10 + $10 = $20
Where n = day of the month
Explicit formula :
y = a + b(c - 1)
WHERE:
y = final amount
initial amount = a
Increment on initial amount = b
Day of the month = c
THE ARNOLD'S :
Recursive formula:
First day of the month (A1) = $10
An = 2(An-1)
A2 = 2(A1) = 2(10) = $20
A3 = 2(A2) = 2(20) =$40
Explicit formula:
y = a(b)^c
Where :
y = final amount
initial amount = a
Increment on initial amount = b
Day of the month = c
Answer:
The answer would be D, 37/2 divided by 17/4
Explanation:
I did the test.
Answer:
Water needed for pool = 486 cubic feet
Plastic liner required for the pool = 298.3 feet
Step-by-step explanation:
Top view of the pool is a composite figure, having one rectangle and a trapezoid.
1). Water needed for the pool = volume of the pool
Volume of the pool = Area of the base × Depth
= (Area of the rectangle + Area of the trapezoid)× depth
Area of the trapezoid = 
= 
= 105 ft²
Area of the rectangle = Length × width
= 11 × 1.5
= 16.5 ft²
Now, volume of the pool = (105 + 16.5) × 4
= 121.5 × 4
= 486 cubic feet
b). Liner required = surface area of the pool excluding top
= Surface area of the walls + Area of the pool base
= (Perimeter of the pool) × depth + area of the base
= (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5
= 176.8 + 121.5
= 298.3 square feet
Therefore, amount of water required = 486 cubic feet
liner needed = 298.3 square feet
A^2 + 31 = 155 - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)