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ioda
2 years ago
10

Derivative of the following cos(x^{2} y)=y^{2}

Mathematics
1 answer:
MatroZZZ [7]2 years ago
3 0

Answer:

\cos( {x}^{2}y )  =  {y}^{2}  \\  \frac{d( \cos( {x}^{2}y) ) }{dx}  =  \frac{d( {y}^{2}) }{dx}  \\ (2xy +  {x}^{2} \frac{dy}{dx}  ).( -  \sin( {x}^{2} y) ) = 2y \frac{dy}{dx}  \\   \frac{- 2xy \sin( {x}^{2}y )   -  {x}^{2}  \sin( {x}^{2} y) }{2y}  =  \frac{dy}{dx}  \\

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kkurt [141]

Let's solve for x.

−x+9y=−5

Step 1: Add -9y to both sides.

−x+9y+−9y=−5+−9y

−x=−9y−5

Step 2: Divide both sides by -1.

−x ÷ −1 = −9y−5 ÷ −1

x=9y+5

THE ANSWER FOR THE OTHER EQUATION: (x-5y=1)

Let's solve for x.

x−5y=1

Step 1: Add 5y to both sides.

x−5y+5y=1+5y

x=5y+1

Answer:

x=5y+1

I hope this helped I was a little confused on what your problem meant...so if this is not what you asked for just lmk so I can fix it for you :)

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Step-by-step explanation:

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