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3 years ago

14

A triangular flower bed is to be created. The following figure represents the layout of the flower bed. How many feet of landsca

pe edging would be
required to outline the edge of the bed?
15 ft
17 ft

1 answer:

VladimirAG [237]3 years ago

8 0

Answer:

8 feet

Step-by-step explanation:

The diagram is attached below.

Note that the values are different but the diagram is similar. In this case,

Hypotenuse =17ft

Adjacent = 15²

Required

Opposite side

To get the feet of landscape edging would be required to outline the edge of the bed, we will use the Pythagoras theorem as shown;

Hyp² = Opp²+Adj²

Opp² = Hyp²-Adj²

l² = 17²-15²

l² = 289-225

l² = 64

l = √64

l = 8feet

Hence the feet of landscape edging would be required to outline the edge of the bed is 8 feet

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Answer:

The circumference of the circle is 28.26 m.

The area of the circle is 63.585 $m^{2}$ .

Step-by-step explanation:

To solve for the circumference of the circle, start by using the circumference formula of a circle, which is $C= 2\pi r$ . However, 3.14 will be used instead of $(\pi)$ for this formula.

First, the radius of the circle needs to be found. To find the radius of the circle, divide the diameter by 2 because the radius equals half of the diameter. The radius is 9 m divided by 2, which equals 4.5 m.

Next, plug in the radius into the formula, and the formula will look like $C=(2)(\pi )(4.5 m)$ . Then, solve the equation, and the answer will be 28.26 m.

To solve for the area of the circle, start by using the area formula of a circle, which is $A=\pi r^{2}$ . However, 3.14 will be used instead of $(\pi)$ for this formula.

For the area, plug the radius into the formula, and the formula will look like $A= (3.14)(4.5m)^{2}$ . Then, solve the equation, and the answer will be 63.585 $m^{2}$ .

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What is the solution to this inequality?

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3 years ago

Part A: Plot the points A(-8,7) and B(6,-9). Mark the halfway point on AB and label it point M. What are the coordinates of M? P

vredina [299]

Answer:

a. $M(x,y) = (-1,-1)$

b. $D(-4,-9)$

Step-by-step explanation:

Given

A(-8,7) and B(6,-9).

Solving (a):

Determine the Midpoint M;

This is calculated as follows;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$(x_1,y_1) = (-8,7)$

$(x_2,y_2) = (6,-9)$

Substitute these values in the formula

$M(x,y) = (\frac{-8+6}{2},\frac{7-9}{2})$

$M(x,y) = (\frac{-2}{2},\frac{-2}{2})$

$M(x,y) = (-1,-1)$

<em>Hence; the midpoint is (-1,-1)</em>

Solving (a):

Here, we have

C = (2,7)

M; Midpoint = (-1,-1)

Required: Determine D

This is calculated as follows;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$(x_1,y_1) = (2,7)$

$(x,y) = (-1,-1)$

Substitute these values in the formula

$(-1,-1) = (\frac{2+x_2}{2},\frac{7+y_2}{2})$

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$-1 = \frac{2 + x_2}{2}$

Multiply both sides by 2

$-2 = 2 + x_2$

Subtract 2 from both sides

$x_2 = -2 - 2$

$x_2 = -4$

Solving for y2

$-1 = \frac{7 + y_2}{2}$

Multiply both sides by 2

$-2 = 7 + y_2$

Subtract 7 from both sides

$y_2 = -2 - 7$

$y_2 = -9$

Hence, the coordinates of D is

$D(-4,-9)$

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