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dsp73
3 years ago
14

A triangular flower bed is to be created. The following figure represents the layout of the flower bed. How many feet of landsca

pe edging would be
required to outline the edge of the bed?
15 ft
17 ft
Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

8 feet

Step-by-step explanation:

The diagram is attached below.

Note that the values are different but the diagram is similar. In this case,

Hypotenuse =17ft

Adjacent = 15²

Required

Opposite side

To get the feet of landscape edging would be required to outline the edge of the bed, we will use the Pythagoras theorem as shown;

Hyp² = Opp²+Adj²

Opp² = Hyp²-Adj²

l² = 17²-15²

l² = 289-225

l² = 64

l = √64

l = 8feet

Hence the feet of landscape edging would be required to outline the edge of the bed is 8 feet

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B is the right answer for  this 

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4 years ago
The area of a certain desert desert one is five times the area of another desert desert 2 if the sum of their areas is 24, 000,
sweet-ann [11.9K]

4,000,000 and 20,000,000 miles²

let x be the area of one desert then 5x is the area of the other

sum = x + 5x = 24,000,000

6x = 24,000,000

divide both sides by 6

x = 4,000,000

one desert is 4,000,000 miles²

and the other is (5 × 4,000,000)= 20,000,000 miles²


8 0
4 years ago
Read 2 more answers
In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p
hichkok12 [17]

Answer:

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

The probability of success for this case would be:

p =\frac{9}{15}= 0.6 representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.6)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want this probability:

P(X=3)

And uing the probability mass function we got:

P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165

4 0
3 years ago
3,817,773 rounded to nearest 100,000
Eva8 [605]
3,800,000 is the answer
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Find the circumference of the circle. Round your answer to two decimal places if necessary <br> 4cm
ratelena [41]

Answer:

I think its 12.56

Step-by-step explanation:

Multiply 4 and 3.14(thats pi)

7 0
3 years ago
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