Your answer is 0.40 ......................
Answer:
A. Both ends go down.
General Formulas and Concepts:
<u>Algebra II</u>
- End behavior - what the y-values are approaching as x approaches negative infinity or infinity
Step-by-step explanation:
If we graph the function, we can see that when x goes to -∞, y also goes to -∞.
We also see that when x goes to ∞, y <em>still</em> goes to -∞.
Therefore, both ends of the graph would head towards -∞, making A. the correct answer choice.
Answer:
You didn't post the graph choices, but it will look something like the attached photo. I also attached how to put the equation into slope-intercept form and another photo explaining what that means in case you haven't learned!
Step-by-step explanation:
Let a=2018, we can rewrite the question into
substitute back a = 2018, obtained
well, there is something wrong here
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
