All categories

3 years ago

Please answer these two questions

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

3 0

It’s better to have a low score and for the second one thumber I think....

You might be interested in

Solve for x in the diagram below.

marshall27 [118]

Vertical angles are congruent, so:

$4x+50=150\\\\4x=100\\\\x=\boxed{25}$

4 0

2 years ago

without carrying a tank bottoms has the size of 3 to 6 m. Find out how many cans of paint of 2 kg are required to paint the insi

RUDIKE [14]

I think its 3.33 not for sure

7 0

3 years ago

Read 2 more answers

Travis jogged to his friend's house 10 miles away and then got a ride back home. It took him 2 hours longer to jog there than ri

spin [16.1K]

Using the relation between velocity, distance and time, it is found that his jogging rate was of 4.5 mph.

<h3>What is the relation between velocity, distance and time?</h3>

Velocity is <u>distance divided by time,</u> hence:

$v = \frac{d}{t}$

Jogging, his velocity was of v, while the time was of t + 2, for a distance of 10 miles, hence:

$v = \frac{10}{t + 2}$

Riding, his velocity was of 16, while the time was of t, also for a distance of 10 miles, hence:

$v + 16 = \frac{10}{t}$

Then, considering the first equation and replacing in the second:

$\frac{10}{t + 2} + 16 = \frac{10}{t}$

$\frac{10}{t} - \frac{10}{t + 2} = 16$

$\frac{10t + 20 - 10t}{t(t + 2)} = 16$

16t² + 32t - 20 = 0 -> t = 0.5.

Then his jogging rate in mph was:

$v = \frac{10}{0.5 + 2} = 4.5$

More can be learned about the relation between velocity, distance and time at brainly.com/question/24316569

#SPJ1

8 0

2 years ago

Anyone know this....

zepelin [54]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Plsss help me with this:(((

garri49 [273]

Answer:

$\frac{2 {a}^{2} }{3 {b}^{3} } \div \frac{6 {a}^{3} }{5 {b}^{2} } = \frac{2 {a}^{2} }{3 {b}^{3} } \times \frac{5 {b}^{2} }{6 {a}^{3} } = \frac{5}{9ab} \\ \\ \frac{ {x}^{2} - 5x + 6}{ {x}^{2} - 6x + 9} + \frac{4x - 12}{{x}^{2} - 6x + 9} \\ = \frac{{x}^{2} - 5x + 6 + 4x - 12}{{x}^{2} - 6x + 9} \\ = \frac{{x}^{2} - x - 6}{{x}^{2} - 6x + 9} \\ = \frac{(x - 3)(x + 2)}{(x - 3)(x - 3)} \\ = \frac{(x + 2)}{(x - 3)} \\ \\ \frac{3a}{a - b} - \frac{a + 2b}{a - b} \\ = \frac{3a - a + 2b}{a - b} \\ = \frac{2a - 2b}{a - b} \\ = 2\frac{a - b}{a - b} \\ = 2$

7 0

3 years ago