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Vinvika [58]
3 years ago
10

Why does it take more centimeters than inches to measure the same distance?

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0
Because 1 centimeter is smaller than 1 inch, so more centimeters than inches can fit in a given distance. 
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Plz help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
kiruha [24]

Answer:

R2 = 6.44

T2 = 8.82

Whole = 30.42

Step-by-step explanation:

R1 = 2.8 X 3.1

T1 = (1/2) X (2.4) X (5.4)

R2 = (5.4-3.1) X (2.8)  = 6.44

T2 = (1/2) X (11.7-5.4) X (2.8) = 8.82

Whole = (1/2) X (11.7) X (2.4+2.8) = 30.42

4 0
3 years ago
I can never get these answers right omggg I need help!
Alik [6]

Answer:

24-(L times 2) then divide the awnser by 2

Step-by-step explanation:

6 0
2 years ago
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Mr. peters buys 3 1/4 pound of grapes for $4.55 what is the unit cost of the grapes
anastassius [24]
Divide 3 1/4 with 4.55
6 0
3 years ago
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Lostsunrise [7]
100 Is I was just like oh oh and then you are in the church
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3 years ago
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0
3 years ago
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