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My name is Ann [436]
2 years ago
9

What is the equation of the line that is parallel to the line y =1/3 x + 4 and passes through the point (6, 5)?

Mathematics
1 answer:
lianna [129]2 years ago
5 0

Answer:

y = \frac{1}{3} x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{1}{3} x + 4 ← is in slope- intercept form

with slope m = \frac{1}{3}

Parallel lines have equal slopes , then

y = \frac{1}{3} x + c ← is the partial equation

To find c substitute (6, 5) into the partial equation

5 = 2 + c ⇒ c = 5 - 2 = 3

y = \frac{1}{3} x + 3 ← equation of parallel line

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3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)
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Answer:

For the given functions f(x) and g(x) (f-g)(x) = -2x^{2}  - 8x +12

Step-by-step explanation:

Here, the given function are:

f(x)  = 3x^{2}  - 2x+ 4\\g(x) = 5x^{2}  + 6x -8

Now, simplifying for (f-g)(x)  =  f(x) -  g(x):

f(x) - g(x)  = (3x^{2}  - 2x+ 4) - (5x^{2}  + 6x -8)

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Doing operation on LIKE TERMS,  we get

f(x) -  g(x) = ( 3x^{2}- 5x^{2})   + (-2x - 6x)  +( 4 +8) = -2x^{2}  - 8x + 12

Hence, for the given functions f(x) and g(x) (f-g)(x) = -2x^{2}  - 8x +12

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Answer:

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Step-by-step explanation:

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