Answer:
C : 0.167
Step-by-step explanation:
Have a nice day
Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
The answer is quite simple after looking at it. 0.1 is a tenth. 72 is a whole number, so you would have 72 1/10. 1/10 is a tenth and 72 is still the whole number.
Answer:
g
Step-by-step explanation:
The maximum value occurs at gradient 0 (the stationary point).
In f this has a value (y) of 6.
In the equation example we have to differentiate:
dg(x)/dx = -x + 4
Gradient is 0 so 4 - x = 0 so x = 4
Plug g(4)=our maximum=-(1/2)4^2 + 4(4) + 3 = -8 + 16 + 3 = 11
11 > 6 so g has greater maximum.
Answer:
8
Step-by-step explanation:
You do 240 divided by 30 to get 8