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Trava [24]
3 years ago
8

^+^1+9/3^n^-^1+1" align="absmiddle" class="latex-formula">
how do i solve it?
Mathematics
1 answer:
abruzzese [7]3 years ago
4 0

Answer:

Hello,

Step-by-step explanation:

\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\

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An expression is shown below:
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The factored expression is:

3y(x^3 + 4x - 3x^2 - 12)

------------------------

To factor the expression:

  • First, we need to find the greatest common factor of the numeric and symbolic coefficients.
  • Then, we divide each term of the expression by it's gcf.

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The expression is:

3x^3y + 12xy - 9x^2y - 36y

------------------------

The numeric coefficients are: 3, 12, 9, 36

The gcf of the numeric coefficients is:

3 - 12 - 9 - 36|3

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The gcf of the numeric coefficients is 3, as 3 is the only number by which 3, 12, 9 and 36 are all divisible.

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The symbolic coefficients are: x^3y, xy, x^2y, y

The only common term is y, so y is the gcf of the symbolic coefficients.

------------------------

The gcf of the entire expression is the multiplication of the gcfs of the numeric and of the symbolic coefficients, so it is 3y.

Now, to factore the expression:

3x^3y + 12xy - 9x^2y - 36y = 3y(\frac{3x^3y}{3y} + \frac{12xy}{3y} - \frac{9x^2y}{3y} - \frac{36y}{3y}) = 3y(x^3 + 4x - 3x^2 - 12)

The factored expression is:

3y(x^3 + 4x - 3x^2 - 12)

A similar problem is given at brainly.com/question/20691631

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