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Sliva [168]
2 years ago
13

What is the correct answer

Mathematics
1 answer:
jok3333 [9.3K]2 years ago
3 0

Answer:

c

Step-by-step explanation:

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Rewrite 56 + 32 as the product of the GCF and a sum.
lakkis [162]

The right answer is

56 = 2 x 2 x 2 x 732 = 2 x 2 x 2 x 2 x 2 
GCF = 2 x 2 x 2 =8
Rewrite 56+32 as the product of the GCF and a sum:
56 + 32 = 8  (7+4)

3 0
3 years ago
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During a sale at the bookstore,books sold for $3 and magazines sold for $2.50.Jan spent $16 and bought a total of 6 books and ma
quester [9]

<span>If you would like to know how many of each did Jan buy, you can calculate this using the following two equations:

b ... the number of books
m ... the number of magazines

$16 = b * $3 + m * $2.50 ... 16 = 3 * b + 2.50 * m
b + m = 6 ... b = 6 - m
__________________
</span>16 = 3 * b + 2.50 * m

<span>16 = 3 * (6 - m) + 2.50 * m</span>

16 = 3 * 6 - 3 * m + 2.50 * m

16 - 18 = - 3 * m + 2.50 * m

- 2 = - 0.50 * m     /0.50

m = 2 / 0.50

m = 4 magazines 

<span>b = 6 - m = 6 - 4 = 2 books</span>

Result: Jan bought 4 magazines and 2 books.

3 0
3 years ago
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Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian
777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\B=30^o

Applying the law of sines

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(A)}=\frac{2}{sin(30^o)}

sin(A)=1

so

A=90^o

Find the measure of angle C

In a right triangle

we know that

B+C=90^o ----> by complementary angles

B=30^o

therefore

C=60^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{b}{sin(B)}

substitute the given values

\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}

c=2\sqrt{3}\ units

therefore

The dimensions of the triangle are

A=90^o

B=30^o

C=60^o

a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units

<em>Second case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\A=30^o

Applying the law of sines

Find the measure of angle B

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(30^o)}=\frac{2}{sin(B)}

sin(B)=0.25

so

using a calculator

B=14.48^o

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

A=30^o\\B=14.48^o

therefore

30^o+14.48^o+C=180^o

C=135.52^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}

c=5.61\ units

therefore

The dimensions of the triangle are

A=30^o

B=14.48^o

C=135.52^o

a=4\ units\\b=2\ units\\c=5.61\ units

see the attached figure to better understand the problem

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X= 5 x= -9 y = -10 if this not the answer reverse it
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You are on a 5.6-mile run and have already run 1.98 miles. How many more miles do you need to run?
Likurg_2 [28]

Answer:

3.62 miles need to be run

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