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saveliy_v [14]
3 years ago
8

A bag contains 3 red marbles and 6 blue marbles. A second bag contains 6 green marbles and 4 yellow marbles. You choose a marble

from bag A and then a marble from bag B, what would be the probability of selecting one blue marble and one yellow marble?
Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

4/15

Step-by-step explanation:

Bag A

3 red marbles and 6 blue marbles.  = 9 marbles

P(blue) = blue/total =6/9 = 2/3

Bag B

6 green marbles and 4 yellow marbles.  = 10 marbles

P(yellow) = yellow/total=4/10 = 2/5

P(blue,yellow) = 2/3 * 2/5 = 4/15

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