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3 years ago

A wall is 4 1/2 feet long and has an area of 15 3/4 square feet. What is its height in feet?

Mathematics

1 answer:

IRINA_888 [86]3 years ago

5 0

Answer:

3 1/2

Step-by-step explanation:

if you multiply 4 and 3 you 12 if you multiply 1/2 times 3 you get 1 1/2 and 1 1/2 + 12 = 13 1/2 and then you have to find a fraction that when multiplied by 4 1/2 you get 2 1/4 and 4 1/2 × 1/2 = 2 1/4 so 2 1/4 + 13 1/2 = 15 3/4

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The speed of boat in still water is 15km/hr if needs 4 more his to travel 63 km against the current of a river than it needs to

hram777 [196]

Answer:

$\frac{63}{15 - c} - \frac{63}{15 + c} = 4$

Step-by-step explanation:

The systems of equations are

Let us assume the rate of the current be c

Now actual speed against the current is (15 - c)

And, the actual speed with the current is (15 + c)

Here we applied the time formula i.e. distance by speed

Also the upstream time - downstream time = 4

Now the equations are

$\frac{63}{15 - c} - \frac{63}{15 + c} = 4$

5 0

3 years ago

How can i factorise <img src="https://tex.z-dn.net/?f=12x%20-%206" id="TexFormula1" title="12x - 6" alt="12x - 6" align="absmidd

Lorico [155]

Answer:

6(2x - 1)

Step-by-step explanation:

Given

12x - 6 ← factor out common factor of 6 from both terms

= 6(2x - 1) ← in factored form

8 0

3 years ago

Read 2 more answers

Find the mean absolute deviation for the data set. 5,6,6,8,10

alukav5142 [94]

Answer: 1.6

Order the numbers

5,6,6,8,10

Add

5+6+6+8+10=35

Divide

35÷5=7

Mean: 7

Sum divided by the count.

Final Answer: 1.6

6 0

3 years ago

Read 2 more answers

A temperature of –25°c is equivalent to: a. 248 k. b. 25 k. c. –25 k. d. 298 k.

SpyIntel [72]

The temperature T in Kelvin (K) is equal to the temperature T in degrees Celsius (°C) plus 273.15:

T(K) = T(°C) + 273.15;

So, T(K) = -25 + 273.15;

T(K) = 248.15;

The correct answer is a.

7 0

4 years ago

Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor

docker41 [41]

Given:

The table of values is

Number of Students : 7 14 21 28

Number of Textbooks : 35 70 105 140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

$\dfrac{35}{7}=5$

$\dfrac{70}{14}=5$

$\dfrac{105}{21}=5$

$\dfrac{140}{28}=5$

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

$\dfrac{y}{x}=k$

Here, k=5.

$\dfrac{y}{x}=5$

$y=5x$

Hence the rate of change is constant that is 5.

8 0

3 years ago