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zzz [600]
3 years ago
15

!PLEASE HELP ME!

Mathematics
1 answer:
Mkey [24]3 years ago
3 0

Answer:

We conclude that Tim is correct when he says that the expression x² only yields values that are positive.

Step-by-step explanation:

Given the expression

x²

  • Plug in and checking x = 1 and x = -1 in the expression

Putting x = 1 in the expression

x²= (1)² = 1

Putting x = -1 in the expression

x²= (-1)² = 1

Thus, the expression yields the same output '1' when we enter x = 1, and x=-1.

  • Plug in and checking x = 2 and x = -2 in the expression

Putting x = 2 in the expression

x²= (2)² = 4

Putting x = -1 in the expression

x²= (-2)² = 4

Thus, the expression yields the same output '4' when we enter x = 2, and x=-2.

  • Plug in and checking x = 3 and x = -3 in the expression

Putting x = 3 in the expression

x²= (3)² = 9

Putting x = -1 in the expression

x²= (-3)² = 9

Thus, the expression yields the same output '9' when we enter x = 3, and x=-3.

The reason why the expression x² only yields positive values because the expression is in the square form, and the square of any number will always yield a positive value, no matter whether the input number is negative or positive.

Therefore, we conclude that Tim is correct when he says that the expression x² only yields values that are positive.

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PLEASE HELP ASAP
xz_007 [3.2K]
Short answer: Radius of new circle = sqrt(6) * the original radius
 
Area = pi * r^2
A1 = 6*Area = pi * (k * r) ^2
A1 = 6*Area = k^2 * pi * r^2 Set up a proportion.

Proportion
\frac{A}{6*A} =  \frac{ \pi * r^2}{ \pi * k^2 * r^2}

Comment
The As Cancel, the pis cancel the r^2 cancel.

1/6 = 1 / k^2  Cross multiply
k^2 = 6 Take the square root of both sides.
sqrt(k^2) = sqrt(6)
k = sqrt(6)

Conclusion
The radius increases by a factor of sqrt(6) times.

Discussion. You may not like this method very much, but you will do a lot of it in Physics or Chemistry. You may prefer the second method.

Step One
Find the area of the original circle
Area = pi * r^2
r = 10.9
pi = 3.14
Area = pi * r^2
Area = 3.14 * 10.9^2
Area = 3.14 * 118.81
Area = 373.1

Step 2
Multiply this area by 6
Area1 = 6 * Area
Area1 = 6 * 373.1
Area1 = 2238.38

Step 3
Find the radius of the bigger circle
Area1 = 2238.38
pi = 3.14
r = ????

Area1 = pi * r^2
2238.38 = 3.14 * r^2 Divide both sides by 3.14
2238/3.14 = r^2
r^2 = 712.86              Take the square root of both sides.
sqrt(r^2) = sqrt(712.86)
r = 26.6994

Step 4
Divide by the original r
r/10.9 = 26.6994 / 10.9 = 2.44948

Here's where this get's a little messy. How do you know what to do with this. Perhaps just saying that the new radius = the original radius * 2.44958

But try taking the square root of 6 to see what happens.
sqrt(6) = 2.449489 is what you get, so the radius increases by sqrt(6) in size.

Comment
No matter which way you do this, it looks like a messy problem just because square root 6 is not easily recognized.
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The coefficients in the equation (-x)(3y)(-2x) are the constants -1, 3, and -2. 
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</span><span>The commutative law</span> says hat you can rearrange a multiplication any way you want. so, (-1)*3*(-2)=(-3)*(-2)=6
The equation can be also simplified written as:
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None of the option is the solution.
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