<span>Length = 1200, width = 600
First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as:
W = (2400 - L)/2
And area is:
A = LW
Substitute the equation for width, giving:
A = LW
A = L(2400 - L)/2
And expand:
A = (2400L - L^2)/2
A = 1200L - (1/2)L^2
Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
A = 1200L - (1/2)L^2
A = 1200(1200+e) - (1/2)(1200+e)^2
A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
A = 720000 - (1/2)e^2
And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
Answer:
$159
Step-by-step explanation:
we know that
The equation of a exponential growth function is equal to
where
y is the balance in the saving account
x is the number of years
a is the initial amount
r is the percent rate of change
we have
substitute
For x= 1 year
substitute
Amount of Interest = $36
Rate of interest = 3% per annum
Total time period for which the money was invested = 3 years
Let us assume the Principal amount = x
Then
Interest = Principal * Rate of Interest * time
36 = x * 3% * 3
36 = 9x/100
36 * 100 = 9x
3600 = 9x
x = 3600/9
= 400
So the initial sum of the money that was invested was $400.
The first one is 4 and the last one is 2.14237024 u can put all of that in if u want
Quadrant 3
Since both the x and y are negative, it will be in the third quadrant.
