A(squared)+B(squared)=C(squared)
Answer:
Bryce is wrong in step 1 because he did not distribute 3 over 5/3
Explanation
Given the steps taken by bryce as shown, we are to find where he made an error

Given the expression;

Step 1:Expand the bracket using the distributive law;
8/3 = 3c + 3(5/3)
<em>Simplify</em>
8/3 = 3c + 15/3
Step 2: Subtract 15/3 from both sides
8/3 - 15/3 = 3c+15/3-15/3
(8-15)/3 = 3c
-7/3 = 3c
Step 3: Multiply both sides by 1/3
-7/3 * 1/3 = 3c * 1/3
-7/9 = c
Swap
c = -7/9
From the calculation, we can see that Bryce is wrong in step 1 because he did not distribute 3 over 5/3 thereby making his solution incorrect
Answer:
Step-by-step explanation:
Given two upward facing parabolas with equations

The two intersect at


=
x=
area enclosed by them is given by
A=![\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx](https://tex.z-dn.net/?f=%5Cint_%7B-%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5E%7B%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5Cleft%20%5B%20%5Cleft%20%28%20x%5E2%2B2%5Cright%20%29-%5Cleft%20%28%206x%5E2%5Cright%20%29%20%5Cright%20%5Ddx)
A=
A=
A=
Answer:


Step-by-step explanation:
Let the length of the rectangle be 'L'
And the width of the rectangle be 'W'

According to the statement:

Perimeter of a rectangle= 2(Length+Width)



A bicyclist travels at a constant speed of 12 miles per hour for a total of 45 minutes.
We know the formula , Distance = speed * time
Speed is constant and it is 12. So it is linear
The function becomes d = 12t, x is the t is the time and d is the distance
At the starting point, t=0 and distance d=0
End point , t=45 min = 0.75 hours and distance = 12 * 0.75 = 9
So domain (t) is {
}
Range (d) is {
}