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3 years ago

8

Simplify 12 to the sixteenth power over 12 to the fourth power

1 answer:

tangare [24]3 years ago

6 0

Hi there!

So, it looks like this. 12^16 / 12^4. Do the "Quotient Rule." (A.K.A, subtracting both powers. 12^16 / 12^4 = 12^12. 12^12 = 8,916,100,448,256. (Yes, it's a scarily huge number..)

Hope this helps! ☺♥

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20 POINTS Compost costs $10 per cubic yard and topsoil costs $2 per cubic yard. Maria needs more than 10 cubic feet of topsoil.

Morgarella [4.7K]

I can't see the graph but let's use logic
hmm, more than 10 cubic feet of topsoil so the first and 2nd options are wrong

let's ee the costs
3rd option
10*1=10
2*12=24
10+24=34 and 34<50, that is fine

4th option
3*10=30
2*12=24
30+24=54
54>50, nope, that is over cost

answer is 3rd one
the one with 1 cubic yard compost and 12 cubic yard topsoil

8 0

3 years ago

Read 2 more answers

Bowser ate 4 1/2 pounds of dog food.That amount is 3/4 of the entire bog of dog food. How many pounds of dog food were originall

Molodets [167]

Answer:

because it is 3/4 of the entire bag, there has to be a Ratio:

3:4 = 4.5:w

\frac{3}{4} \frac{4.5}{w}

cross mult.

3w= 4.5(4)

3w = 18

divide 3 both sided

18/3=6

w=6

6lbs of food.

Therefore, your ans is 6lbs of dog food

Step-by-step explanation:

4 0

3 years ago

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |<em>multiply both sides by $\sqrt{13}$ </em>

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |<em>divide both sides by 3</em>

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

4 0

2 years ago

Simplify 8r - 3j + 9j - 2r

Shkiper50 [21]

Answer:

6j + 6r :)))))))))))))))))

3 0

2 years ago

Read 2 more answers

Carla and Jonah are working together to determine if quadrilateral CDEF with coordinates C(2, 3), D(1, 2), E(4, 1), and F(5, 3)

alukav5142 [94]

Answer:

Option (B)

Step-by-step explanation:

CDEF is a quadrilateral having vertex C(2, 3), D(1, 2), E(4, 1), F(5, 3).

To prove that the given quadrilateral has a right angle, we will use the property of perpendicular lines.

$m_1\times m_2=-1$

where $m_1$ and $m_2$ are the slopes of the consecutive sides of the quadrilateral.

Since CD and DE are the consecutive sides of the quadrilateral, Carla is on the right track by finding the slopes of CD and DE.

Since Jonah is finding the slopes of opposite sides so he will not be able to use the property of perpendicular lines.

Option (B) will be the answer.

3 0

3 years ago