C The number and types of bonds within the molecule.
Explanation:
In a molecule, the number and types of bonds present determines the amount of available energy therein.
When bonds are broken or formed, energy is usually released.
- Elements combine with one another in order to attain stability in this state.
- Through this process, they form bonds by attraction.
- Where atoms exchange their valence electrons by losing or gaining it, electrovalent bonds form.
- In covalent molecules, electrons are usually shared between atoms.
- An attraction result from this type of interaction.
- The bond formed stores energy in the process.
- When bonds are broken, energy is usually released. The energy accrues when the bond was being formed.
- In molecules, we have covalent bond.
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The answer is B atmosphere (clouds )
The volume of the gas is 180.26 L, if there are 63.5 mol of an ideal gas at 9.11 atm at 42.80 °C.
Applying the ideal gas law PV= nRT
After rearranging the aforementioned expression, the volume might then be found as: V= n R T/ P.
Consequently, V= 63.5 mol, 0.0821, 315 K, and 9.11 atm equal 180.26 L.
<h3>How is the ideal gas equation defined?</h3>
The ideal gas equation is PV = nRT. In this equation, P denotes the ideal gas's pressure, V its volume, n its total amount, expressed in moles, and R its resistance for the universal gas constant, and T for temperature.
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Answer:
Explanation:
To make a distinction in favor of or against a person or thing on basic or group, class or category, to which the person or thing(s) belong
I am assuming that the balanced equation is
2H₂ + O₂ ⇒ 2H₂O
Since the hydrogen is the limiting reagent (meaning if the hydrogen runs out the reaction stops), we need to compare the mole ratio between hydrogen and water.
The mole ratio between H₂ and H₂O is 2:2, or 1:1 (as seen on the coefficients of the balanced equation)
And so for every mole of hydrogen, it will be equal to water. Since hydrogen is 4 moles, 4 moles of water would be created.
So we use the coefficients of H₂ and H₂O in order to answer this question.
