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chubhunter [2.5K]

3 years ago

7

Which is a substance that could be found in air, water or soil that is harmful to humans or animals?

1 answer:

tatyana61 [14]3 years ago

6 0

Hello!

A substance that could be found in air, water or soil that is harmful to humans or animals is a Pollutant.

The other substances cannot be found in air, water or soil. Fossil fuels can only be found in soil, smog can only be found in the air, and carbon dioxide can be found in the water or air.

Pollutants are substances that have harmful effects and damage the environment. Some examples of pollutants are Carbon Monoxide (air), Lead (soil) and Insecticides (water).

Have a nice day!

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Suppose a 250 ml flask is filled with 1.3mol of O2 and 1.5 mol of NO. The following reaction becomes possible: The equilibrium c

bonufazy [111]

<u>Answer:</u> The equilibrium molarity of oxygen gas is 7.1 M

<u>Explanation:</u>

We are given:

Moles of oxygen gas = 1.3 mole

Moles of NO = 1.5 moles

Volume of the flask = 250 mL = 0.250 L (Conversion factor: 1 L = 1000 mL)

To calculate the molarity, we use the equation:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume of solution (in L)}}$

Molarity of oxygen gas = $\frac{1.3}{0.25}=5.2M$

Molarity of NO = $\frac{1.5}{0.25}=6.0M$

The chemical equation follows:

$O_2+N_2\rightleftharpoons 2NO$

Initial: 5.2 - 6.0

At eqllm: 5.2+x +x 6.0-2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NO]}{[O_2][N_2]}$

$K_c=0.394$ (Assuming)

Putting values in above equation, we get:

$0.394=\frac{(6.0-2x)^2}{(5.2+x)\times x}\\\\-3.606x^2+26.0488x-36=0\\\\x=1.9,5.4$

Neglecting the value of x = 5.4 because this cannot be greater than the initial value.

Concentration of oxygen gas at equilibrium = (5.2 + x) = 5.2 + 1.9 = 7.1 M

Hence, the equilibrium molarity of oxygen gas is 7.1 M

8 0

3 years ago