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3 years ago

Which is a substance that could be found in air, water or soil that is harmful to humans or animals?

1 answer:

6 0

Hello!

A substance that could be found in air, water or soil that is harmful to humans or animals is a Pollutant.

The other substances cannot be found in air, water or soil. Fossil fuels can only be found in soil, smog can only be found in the air, and carbon dioxide can be found in the water or air.

Pollutants are substances that have harmful effects and damage the environment. Some examples of pollutants are Carbon Monoxide (air), Lead (soil) and Insecticides (water).

Have a nice day!

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To what extent do covalent compounds conduct electricity?

sertanlavr [38]

The answer is never because there's no electricity

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3 years ago

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A team of scientists is studying the fossils in the cross-section of rock shown below. Between which two layer of fossils can se

Gennadij [26K]

Question:

Layer 1 and 2 → Animal fossil

Layer 3 and 4 → First plant fossil

Layer 5 → Animal fossil

Layer 6→ Second plant fossil

Layer 7 → Animal fossil.

Answer:

The correct option to choose answer is;

C) Layers 3 and 4 (Secondary succession layer).

Explanation:

Secondary succession is a concept related to pliant life and it describes the notion of an ecosystem regenerates after being destroyed and it takes place when the level of disruption is not enough to do away with all present vegetation and present soil from a location.

Secondary succession is started by an incident that destroys to a large extent the present ecosystem. Events that start secondary succession includes;

1) Hurricane

2) Fire and

3) Harvesting.

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3 years ago

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Which type of reaction occurs in the core of a nuclear reactor in a nuclear power plant? Upper H upper C l plus upper N a upper

Sav [38]

Answer:

Superscript 235 subscript 92 upper U plus superscript 1 subscript 0 n right arrow superscript 90 subscript 38 upper S r plus superscript 143 subscript 54 upper X e plus 3 superscript 1 subscript 0 n.

Explanation:

4 0

3 years ago

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You wish to measure the iron content of the well water on the new property you are about to buy. You prepare a reference standar

torisob [31]

Based on Beer-Lambert's Law,

A = εcl ------(1)

where A = absorbance

ε = molar absorptivity

c = concentration

l = path length

Step 1: Calculate the concentration of the diluted Fe3+ standard

Use:

V1M1 = V2M2

M2 = V1M1/V2 = 10 ml*6.35*10⁻⁴M/55 ml = 1.154*10⁻⁴ M

Step 2 : Calculate the concentration of the sample solution

Based on equation (1) we have:

A(Fe3+) = ε(1.154*10⁻⁴)(1)

A(sample) = ε(C)(4.4)

It is given that the absorbances match under the given path length conditions, i.e.

ε(1.154*10⁻⁴)(1) = ε(C)(4.4)

C = 0.262*10⁻⁴ M

This is the concentration of Fe3+ in 100 ml of well water sample

Step 3: Calculate the concentration of Fe3+ in the original sample

Use V1M1 = V2M2

M1 = V2M2/V1 = 100 ml * 0.262*10⁻⁴ M/35 ml = 7.49*10⁻⁵M

Ans: Concentration of F3+ in the well water sample is 7.49*10⁻⁵M

7 0

3 years ago

1. For every 5.00 mL of milk of magnesia there are 400. mg of magnesium hydroxide. How many mL of milk of magnesia do we need to

forsale [732]

Answer:

1. 6.50mL

2. pH = 13.097

Explanation:

1. The neutralization of HCl with Al(OH)₃ is:

3HCl + Al(OH)₃ → Al(Cl)₃ + 3H₂O

40.0mL ≡ 0.0400L of 0.500M HCl are:

0.0400L × (0.500mol / L) = 0.0200 moles of HCl

Based on the neutralization, 3 moles of HCl react with 1 mole of Al(OH)₃, thus, the moles of Al(OH)₃ that react with 0.0200 mol of HCl are:

0.0200mol HCl × (1mol Al(OH)₃ / 3mol HCl) = 0.00667 moles of Al(OH)₃. In grams:

0.00667 moles Al(OH)₃ × (78g / 1mol) = 0.520g of Al(OH)₃ ≡ 520mg

As 5.00mL of milk magnesia contain 400mg of Al(OH)₃, the mL of milk magnesia required for a complete reaction are:

520 mg Al(OH)₃ × (5.00mL / 400mg) = 6.50mL

2. The reaction of lithium hydroxide (LiOH) with perchloric acid (HClO₄) is:

HClO₄ + LiOH → LiClO₄ + H₂O

The reaction is 1:1.

Moles of LiOH and HClO₄ are:

LiOH: 0.0500L × (0.350mol / L) = 0.0175 moles of LiOH

HClO₄: 0.0300L × (0.250mol / L) = 0.0075 moles of HClO₄

Assuming the reaction goes to completion, moles of LiOH that remains are:

0.0175 mol - 0.0075 mol = 0.0100 moles of LiOH. The total volume is 80.0mL, 0.0800L. Thus, molarity of LiOH is:

0.0100 mol / 0.0800L = 0.125 M of LiOH

It is possible to obtain the pOH of the solution thus:

pOH = -log (OH) = -log 0.125M = 0.903

As pH = 14- pOH,

pH = 14 - 0.903 = 13.097

I hope it helps!

3 0

3 years ago