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Lubov Fominskaja [6]
3 years ago
6

Awnser photo quick please #2

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

2 4 5 8

Step-by-step explanation:

the numbers must be positioned in ascending order

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The height of a certain banner is equal to one third of its length. If the banner is 5 ft tall, write the equation that can be u
pav-90 [236]

Answer:

L=3h

Step-by-step explanation:

Let height of a banner be h, then we know that this is \frac{1}{3} of the length L of the banner; so we have

h=\frac{1}{3} L .

Now we can rearrange this equation to solve for the length of the banner given it's height:

L=3h

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5 0
3 years ago
What is the pressure difference Δp=pinside−poutside? Use 1.28 kg/m3 for the density of air. Treat the air as an ideal fluid obey
Sidana [21]

This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, 1.11\times 10^3Pa

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = \rho=1.28kg/m^3

Area = A = 7.00 m × 12.0 m

Formula used :

\Delta P=\frac{1}{2}\times \rho \times v^2

Now put all the given values in this formula, we get:

\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2

\Delta P=1.11\times 10^3Pa

Thus, the pressure difference will be, 1.11\times 10^3Pa

7 0
4 years ago
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