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worty [1.4K]
2 years ago
6

Round 0.293263 to the ten thousandths place

Mathematics
2 answers:
gladu [14]2 years ago
5 0

Answer:

0.293263 rounded to the ten thousandths place

=0.2933

wlad13 [49]2 years ago
4 0

Answer:

0.2933

Step-by-step explanation:

0.293263 is the decimal you have to round.

0.<u>2</u>93263 (the first 2 is in the tenths place)

0.2<u>9</u>3263 (the 9 is in the hundredths place)

0.29<u>3</u>263 (the first 3 is in the thousandths place)

0.293<u>2</u>63 (the second 2 is in the ten-thousandths place)

0.2932<u>6</u>3 (the 6 is in the hundred-thousandths place)

0.29326<u>3</u> (the second 3 is in the millionths place)

They tell you to round the decimal to the ten thousandths place.

The second 2 is in the ten-thousandth place (0.293<u>2</u>63).

To round digits you look at the number to its right, if it is 5-9 you round the number up, if it is 0-9 you leave the number as it is.

The number to the right of the number we're rounding (the 2 in the ten-thousands place) is a 6, 6 is a 5-9 number so we round the ten-thousands place digit up 1 number, (from 2 to 3).

And we have our rounded number 0.293<u>3</u>

<u></u>

Hope that helped... Chow!

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grigory [225]
For 12, you would do 90=4x+42, and 48=4x, and x=12
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3 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
wlad13 [49]

Answer:

\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}

Step-by-step explanation:

To solve the question we refresh our knowledge of the quotient rule.

For a function f(x) express as a ratio of another functions u(x) and v(x) i.e

f(x)=\frac{u(x)}{v(x)}\\, the derivative is express as

\frac{df(x)}{dx}=\frac{v(x)\frac{du(x)}{dx}-u(x)\frac{dv(x)}{dx}}{v(x)^{2} }

from y=lnx/x^{2}

we assign u(x)=lnx and v(x)=x^2

and the derivatives

\frac{du(x)}{dx}=\frac{1}{x}\\\frac{dv(x)}{dx}=2x\\.

Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e y=lnx\\\frac{dy}{dx}=\frac{1}{x}

If we substitute values into the quotient expression we arrive at

\frac{dy}{dx}=\frac{(x^{2}*\frac{1}{x})-(2x*lnx)}{x^{4}}\\\frac{dy}{dx}=\frac{x-2xlnx}{x^{4}}\\\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}

8 0
3 years ago
Boyd grows only tomatoes and raspberries in his garden. Last year, he grew 140 pounds of tomatoes and 60 pounds of raspberries.
nadya68 [22]

Answer:

29%.

Step-by-step explanation:

We have been given that Boyd grew 140 pounds of tomatoes and 60 pounds of raspberries. This year, the production, by weight, of tomatoes declined by 20 percent, and the production, be weight, of raspberries declined by 50 percent.

First of all, we will find the weight of tomatoes and raspberries using the given information.

Since the production, by weight, of tomatoes declined by 20 percent, so this year production of tomatoes is 80% of 140 pounds.

\frac{80}{100}\times 140=0.80\times 140=112

Since the production, be weight, of raspberries declined by 50 percent, so this year production of raspberries is 50% of 30 pounds.

\frac{50}{100}\times 60=0.50\times 60=30

Total production this year: 112+30=142 pounds.

Now, we will percent decrease formula.

\text{Percent decrease}=\frac{\text{Initial value-Final value}}{\text{Initial value}}\times 100

\text{Percent decrease}=\frac{(140+60)-142}{140+60}\times 100

\text{Percent decrease}=\frac{(200)-142}{200}\times 100

\text{Percent decrease}=\frac{58}{200}\times 100

\text{Percent decrease}=0.29\times 100

\text{Percent decrease}=29

Therefore, the total yield, by weight, of Boyd's garden declined by 29%.

5 0
3 years ago
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AnnyKZ [126]

Answer:

B. Q' (1, 2)

Step-by-step explanation:

im good like that :)

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Gabriele's Pie Shop sold 80 pies last month: 7/10 were apple pies and 1/10 were peach pies. How many pies were neither apple nor
AleksAgata [21]

Answer:

16 pies were neither apple nor peach.

Step-by-step explanation:

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7 0
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