Answer:
5x^4 -37x^3 -6x^2 +41x -6
Step-by-step explanation:
We simplify this expression by removing parentheses and combining like terms. Parentheses are removed using the distributive property.
<h3>Form the product</h3>
The product of the final pair of polynomials in parentheses is ...
(-4x^3 +5x -1)(2x -7) = (-4x^3 +5x -1)(2x) +(-4x^3 +5x -1)(-7)
= -8x^4 +10x^2 -2x +28x^3 -35x +7
= -8x^4 +28x^3 +10x^2 -37x +7
<h3>Combine with remaining sums</h3>
= (5x^4 -9x^3 +7x -1) + (-8x^4 +4x^2 -3x +2) - (-8x^4 +28x^3 +10x^2 -37x +7)
= (5 -8 -(-8))x^4 +(-9 -28)x^3 +(4 -10)x^2 +(7 -3 -(-37))x +(-1 +2 -7)
= 5x^4 -37x^3 -6x^2 +41x -6
Answer:
90
Step-by-step explanation:
Answer:
no
Step-by-step explanation:
because a shape is rotational symmetrical when it looks the same after <em>any rotation</em> by partial turn.
Answer: Our required probability is 0.328.
Step-by-step explanation:
Since we have given that
there is number on the lottery is from 1 to 38.
6 numbers are selected.
We need to find the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket.
So, it should be other than 6 numbers.
Remaining numbers = 38-6 = 32
So, our probability becomes
Hence, our required probability is 0.328.
10 to the power of 1 = 10
5 x 10 = 50
