I'm guessing there are 12 lions since half of twelve is 6 and there is only 2 male lions. I would put down 12. Hope that helps!
Answer:
$6.25 marked up 25% is $7.81
Step-by-step explanation:
First, you have to find what 25% is of 6.25.
Step 1: Our output value is 25.
Step 2: We represent the unknown value with x.
Step 3: From step 1 above, 25=100%.
Step 4: Similarly, x=6.25%.
Step 5: This results in a pair of simple equations:
25=100%(1)
x=6.25%(2)
Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both
equations have the same unit (%); we have
<u>25 </u> = <u>100</u>
x 6.25
Step 7: Again, the reciprocal of both sides gives
<u> x </u> = <u>6.25</u>
25 100
x= 1.5625
x≈ 1.56
Once you've known what 25% is, you add it to 6.25.
1.56+6.25= 7.81
Question:
The options are;
A. The distances in the Olympic final were farther on average.
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
C. The distances in the Olympic final were all greater than the US qualifier distances
D. none of the above
Answer:
The correct option is;
A. The distances in the Olympic final were farther on average.
Step-by-step explanation:
From the options given, we have
A. The distances in the Olympic final were farther on average.
This is true as the sum of the 5 points divided by 5 is more in the Olympic final
B. The distances in the Olympic final varied noticeably more than the US qualifier distances
This is not correct as the difference between the upper and lower quartile in the Olympic final is lesser than in the qualifier
C. The distances in the Olympic final were all greater than the US qualifier distances
This is not correct as the max of the qualifier is more than the lower quartile in the Olympic final
D. none of the above
We have seen a possible correct option in option A
Answer:
f(x)=(2x-7)^7(x+3)^4
When y=0, (2x-7)^7=0 and x=3.5 OR
(x+3)^4=0, and x=-3
Look at x=h or f(2)
That is 96-56-44+2 and it is not equal to 0. (x-2) is not a factor.
x^3-5x^2+6x-30
after trying 1,2, and 3, I tried 5
5/1===-5===6===-30
==1===0====6====30
(x^2-6) with no remainder
the factors are (x-5)(x^2+6)
the zeroes are 5, +/- i sqrt (6). Only one real 0.
hope this helps let me know in the comments if i'm wrong
Answer:
Answer in the picture posted
