<span>First, we write an equation to represent that the fencing lengths add up to 568 feet. we call the side of the fence that has three segments of its length x and the side with only two segments y. We write 3x + 2y = 568. We also know that the area of the rectangle is equal to xy, so area = xy. We put y in terms of x using our first equation and find that y = (568 - 3x)/2. We plug this into our area equation and find that area = (568x - 3x^2)/2. To find the maximum we set the derivative equal to 0 and end up with 0 = 284 - 3x. We solve for x and get 94 and 2/3. We then put that into our first equation to find y = 142. So the dimensions that maximize the area are 94 2/3 x 142.</span>
Step-by-step explanation:
This equation is in Standard Form. To find the x and y intercepts, it is easier to convert it to slope-intercept form, or y = mx + b.
6x - y = 10
-y = -6x + 10
y = 6x - 10
In slope-interecept form, you can see that the y-int, b, is -10, the constant. To find x, set y to zero.
0 = 6x - 10
10 = 6x
10/6 = x
5/3 = x
Answer:
90 degrees looks t like the measure of that angle
Answer:
16
Step-by-step explanation:
16 × 16 = 256
√256 = 16
hope this helps...
